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  • Oracle “CONNECT BY” (层级递归查询)

    Oracle “CONNECT BY”是层次查询子句,一般用于树状或者层次结果集的查询。其语法是:

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    [ START WITH condition ]
    CONNECT BY [ NOCYCLE ] condition

    The start with .. connect by clause can be used to select data that has a hierarchical relationship (usually some sort of parent->child (boss->employee or thing->parts).

     

    说明: 
    1. START WITH:告诉系统以哪个节点作为根结点开始查找并构造结果集,该节点即为返回记录中的最高节点。 
    2. 当分层查询中存在上下层互为父子节点的情况时,会返回ORA-01436错误。此时,需要在connect by后面加上NOCYCLE关键字。同时,可用connect_by_iscycle伪列定位出存在互为父子循环的具体节点。 connect_by_iscycle必须要跟关键字NOCYCLE结合起来使用

     

        接下来,用一些示例来说明“CONNECT BY”的用法。

     

    [例1]

    创建一个部门表,这个表有三个字段,分别对应部门ID,部门名称,以及上级部门ID

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    -- Create table
    create table DEP
    (
      DEPID      number(10) not null,
      DEPNAME    varchar2(256),
      UPPERDEPID number(10)
    )
    ;

    初始化一些数据

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    SQL> INSERT INTO DEP(DEPID, DEPNAME, UPPERDEPID) VALUES (0, '总经办', null);
    1 row inserted
     
    SQL> INSERT INTO DEP(DEPID, DEPNAME, UPPERDEPID) VALUES (1, '开发部', 0);
    1 row inserted
     
    SQL> INSERT INTO DEP(DEPID, DEPNAME, UPPERDEPID) VALUES (2, '测试部', 0);
    1 row inserted
     
    SQL> INSERT INTO DEP(DEPID, DEPNAME, UPPERDEPID) VALUES (3, 'Sever开发部', 1);
    1 row inserted
     
    SQL> INSERT INTO DEP(DEPID, DEPNAME, UPPERDEPID) VALUES (4, 'Client开发部', 1);
    1 row inserted
     
    SQL> INSERT INTO DEP(DEPID, DEPNAME, UPPERDEPID) VALUES (5, 'TA测试部', 2);
    1 row inserted
     
    SQL> INSERT INTO DEP(DEPID, DEPNAME, UPPERDEPID) VALUES (6, '项目测试部', 2);
    1 row inserted
     
    SQL> commit;
    Commit complete
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    SQL> SELECT * FROM DEP;
     
          DEPID DEPNAME                                                                           UPPERDEPID
    ----------- -------------------------------------------------------------------------------- -----------
              0 General Deparment                                                               
              1 Development                                                                                0
              2 QA                                                                                         0
              3 Server Development                                                                         1
              4 Client Development                                                                         1
              5 TA                                                                                         2
              6 Porject QA                                                                                 2
     
    7 rows selected

    现在我要根据“CONNECT BY”来实现树状查询结果

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    SQL> SELECT RPAD( ' ', 2*(LEVEL-1), '-' ) || DEPNAME "DEPNAME",
    CONNECT_BY_ROOT DEPNAME "ROOT",
    CONNECT_BY_ISLEAF "ISLEAF",
    LEVEL ,
    SYS_CONNECT_BY_PATH(DEPNAME, '/') "PATH"
    FROM DEP
    START WITH UPPERDEPID IS NULL
    CONNECT BY PRIOR DEPID = UPPERDEPID;
     
    DEPNAME                        ROOT                    ISLEAF      LEVEL PATH
    ------------------------------ ------------------- ---------- ---------- --------------------------------------------------------------------------------
    General Deparment              General Deparment            0          1 /General Deparment
     -Development                  General Deparment            0          2 /General Deparment/Development
     ---Server Development         General Deparment            1          3 /General Deparment/Development/Server Development
     ---Client Development         General Deparment            1          3 /General Deparment/Development/Client Development
     -QA                           General Deparment            0          2 /General Deparment/QA
     ---TA                         General Deparment            1          3 /General Deparment/QA/TA
     ---Porject QA                 General Deparment            1          3 /General Deparment/QA/Porject QA
                                                        
    7 rows selected

    说明: 
    1. CONNECT_BY_ROOT 返回当前节点的最顶端节点 
    2. CONNECT_BY_ISLEAF 判断是否为叶子节点,如果这个节点下面有子节点,则不为叶子节点 
    3. LEVEL 伪列表示节点深度 
    4. SYS_CONNECT_BY_PATH函数显示详细路径,并用“/”分隔

    [例2]

    通过CONNECT BY生成序列

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    SQL> SELECT ROWNUM FROM DUAL CONNECT BY ROWNUM <= 10;
     
        ROWNUM
    ----------
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             3
             4
             5
             6
             7
             8
             9
            10
     
    10 rows selected

    [例3]

    通过CONNECT BY用于十六进度转换为十进制

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    CREATE OR REPLACE FUNCTION f_hex_to_dec(p_str IN VARCHAR2) RETURN VARCHAR2 IS
        ----------------------------------------------------------------------------------------------------------------------
        -- 对象名称: f_hex_to_dec
        -- 对象描述: 十六进制转换十进制
        -- 输入参数: p_str 十六进制字符串
        -- 返回结果: 十进制字符串
        -- 测试用例: SELECT f_hex_to_dec('78A') FROM dual;
        ----------------------------------------------------------------------------------------------------------------------
        v_return  VARCHAR2(4000);
      BEGIN
        SELECT SUM(DATA) INTO v_return
          FROM (SELECT (CASE upper(substr(p_str, rownum, 1))
                         WHEN 'A' THEN '10'
                         WHEN 'B' THEN '11'
                         WHEN 'C' THEN '12'
                         WHEN 'D' THEN '13'
                         WHEN 'E' THEN '14'
                         WHEN 'F' THEN '15'
                         ELSE substr(p_str, rownum, 1)
                       END) * power(16, length(p_str) - rownum) DATA
                  FROM dual
                CONNECT BY rownum <= length(p_str));
        RETURN v_return;
      EXCEPTION
        WHEN OTHERS THEN
          RETURN NULL;
      END;

    说明:

    1. CONNECT BY rownum <= length(p_str))对输入的字符串进行逐个遍历

    2. 通过CASE语句,来解析十六进制中的A-F对应的10进制值

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  • 原文地址:https://www.cnblogs.com/Brainpan/p/7248729.html
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