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  • bzoj3931: [CQOI2015]网络吞吐量(spfa+网络流)

    3931: [CQOI2015]网络吞吐量

    题目:传送门

    题解:

      现在有点难受....跳了一个多钟...菜啊...

           题意都把做法一起给了....最短路+网路流啊。

      不想说话...记得开long long 

    #include<cstdio>
    #include<cstring>
    #include<cstdlib>
    #include<cmath>
    #include<algorithm>
    #include<queue>
    #define qread(x)x=read();
    using namespace std;
    typedef long long LL;
    const LL INF=(1LL<<42);
    inline int read()
    {
        int f=1,x=0;char ch;
        while(ch<'0' || ch>'9'){if(ch=='-')f=-1;ch=getchar();}
        while(ch>='0' && ch<='9'){x=x*10+ch-'0';ch=getchar();}
        return f*x;    
    }
    struct edge
    {
        int x,y,next;LL d;
    }e[222222];int last1[222222],len1;
    void ins1(int x,int y,LL d)
    {
        len1++;
        e[len1].x=x;e[len1].y=y;e[len1].d=d;
        e[len1].next=last1[x];last1[x]=len1;
    }
    struct node
    {
        int x,y,next,other;LL d;
    }a[222222];int last[222222],len;
    void ins(int x,int y,LL d)
    {
        int k1,k2;
        len++;k1=len;
        a[len].x=x;a[len].y=y;a[len].d=d;
        a[len].next=last[x];last[x]=len;
        
        len++;k2=len;
        a[len].x=y;a[len].y=x;a[len].d=0;
        a[len].next=last[y];last[y]=len;
        
        a[k1].other=k2;
        a[k2].other=k1;
    }
    int n,m;
    int st,ed,head,tail;
    int list[222222],h[222222];
    bool bt_h()
    {
        memset(h,0,sizeof(h));h[st]=1;
        list[1]=st;head=1;tail=2;
        while(head!=tail)
        {
            int x=list[head];
            for(int k=last[x];k;k=a[k].next)
            {
                int y=a[k].y;
                if(h[y]==0 && a[k].d>0)
                {
                    h[y]=h[x]+1;
                    list[tail++]=y;
                }
            }
            head++;
        }
        if(h[ed]>0)return true;
        return false;
    }
    LL find_flow(int x,LL flow)
    {
        if(x==ed)return flow;
        LL s=0,t;
        for(int k=last[x];k;k=a[k].next)
        {
            int y=a[k].y;
            if(h[y]==(h[x]+1) && a[k].d>0 && flow>s)
            {
                t=find_flow(y,min(a[k].d,flow-s));
                s+=t;
                a[k].d-=t;a[a[k].other].d+=t;
            }
        }
        if(s==0)h[x]=0;
        return s;
    }
    LL dd[222222];
    bool v[222222];
    void spfa()
    {
        for(int i=0;i<=n;i++)dd[i]=INF;
        memset(v,true,sizeof(v));
        memset(list,0,sizeof(list));
        list[1]=st;dd[st]=0;head=1;tail=2;
        while(head!=tail)
        {
            int x=list[head];
            for(int k=last1[x];k;k=e[k].next)
            {
                int y=e[k].y;
                if(dd[y]>dd[x]+e[k].d)
                {
                    //printf("%d %d
    ",x,y);
                    dd[y]=dd[x]+e[k].d;
                    if(v[y]==true)
                    {
                        v[y]=false;
                        list[tail]=y;tail++;if(tail==n+1)tail=1;
                    }
                }
            }
            list[head]=0;
            head++;if(head==n+1)head=1;
            v[x]=true;
        }
    }
    int main()
    {
        //freopen("network.in","r",stdin);
        //freopen("network.out","w",stdout);
        qread(n);qread(m);
        len1=0;memset(last1,0,sizeof(last));
        len=0;memset(last,0,sizeof(last));
        memset(list,0,sizeof(list));
        st=1;ed=n*2;
        for(int i=1;i<=m;i++)
        {
            int x,y;LL d;
            qread(x);qread(y);scanf("%lld",&d);
            ins1(x,y,d);
            ins1(y,x,d);
            //printf("%d %d %lld
    ",x,y,d);
        }
        spfa();
        memset(list,0,sizeof(list));
        for(int i=1;i<=n;i++)
        {
            LL x;scanf("%lld",&x);
            if(i!=1 && i!=n)
            {
                ins(i,i+n,x);
                //printf("%d %d
    ",i,i+n);
            }
        }
        ins(st,1+n,INF);
        ins(n,ed,INF);
        for(int i=1;i<=n;i++)
        {
            for(int k=last1[i];k;k=e[k].next)
            {    
                int y=e[k].y;
                if(dd[i]+e[k].d==dd[y])
                {
                    ins(i+n,y,INF);
                }
            }
        }
        LL ans=0;
        while(bt_h())
            ans+=find_flow(st,INF);
        printf("%lld
    ",ans);
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/CHerish_OI/p/8017247.html
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