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  • Codeforces 891C Envy

    Envy

    感觉这种最小生成树上的啥题都差不多的解法。。

    #include<bits/stdc++.h>
    #define LL long long
    #define fi first
    #define se second
    #define mk make_pair
    #define PLL pair<LL, LL>
    #define PLI pair<LL, int>
    #define PII pair<int, int>
    #define SZ(x) ((int)x.size())
    #define ull unsigned long long
    
    using namespace std;
    
    const int N = 5e5 + 7;
    const int inf = 0x3f3f3f3f;
    const LL INF = 0x3f3f3f3f3f3f3f3f;
    const int mod = 1e9 + 7;
    const double eps = 1e-8;
    const double PI = acos(-1);
    
    int n, m, q, a[N], b[N], w[N], va[N], vb[N], e[N];
    vector<int> vc[N];
    
    int fa[N];
    int getRoot(int x) {
        return fa[x] == x ? x : fa[x] = getRoot(fa[x]);
    }
    
    bool cmp(const int& a, const int& b) {
        return w[a] < w[b];
    }
    
    int main() {
        scanf("%d%d", &n, &m);
        for(int i = 1; i <= n; i++) fa[i] = i;
        for(int i = 1; i <= m; i++) {
            scanf("%d%d%d", &a[i], &b[i], &w[i]);
            vc[w[i]].push_back(i);
        }
        for(int i = 1; i <= 500000; i++) {
            if(!SZ(vc[i])) continue;
            for(auto& x : vc[i]) {
                va[x] = getRoot(a[x]);
                vb[x] = getRoot(b[x]);
            }
            for(auto& x : vc[i]) {
                fa[getRoot(b[x])] = getRoot(a[x]);
            }
        }
        scanf("%d", &q);
        while(q--) {
            bool flag = true;
            int num; scanf("%d", &num);
            for(int i = 1; i <= num; i++) scanf("%d", &e[i]);
            for(int i = 1; i <= num; i++) {
                if(va[e[i]] == vb[e[i]]) {
                    flag = false;
                    break;
                }
            }
            if(!flag) {
                puts("NO");
                continue;
            }
            sort(e + 1, e + 1 + num, cmp);
            for(int L = 1, R = 1; L <= num && flag; L = R) {
                while(R <= num && w[e[R]] == w[e[L]]) R++;
                for(int i = L; i < R; i++) {
                    int x = va[e[i]], y = vb[e[i]];
                    fa[x] = x, fa[y] = y;
                }
                for(int i = L; i < R; i++) {
                    int x = va[e[i]], y = vb[e[i]];
                    int u = getRoot(x), v = getRoot(y);
                    if(u == v) {
                        flag = false;
                        break;
                    }
                    fa[v] = u;
                }
            }
            if(flag) puts("YES");
            else puts("NO");
        }
        return 0;
    }
    
    /*
    */
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  • 原文地址:https://www.cnblogs.com/CJLHY/p/10466934.html
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