zoukankan      html  css  js  c++  java
  • [线段树合并]

    推荐黄嘉泰的线段树合并

    HNOI永无乡

    #include <stdio.h>
    #define maxn 100010
    
    int n, m, id[maxn];
    
    struct Edge{int to, nxt;}edge[maxn << 1];
    int h[maxn], cnt;
    void add(int u, int v){
    	edge[++ cnt] = (Edge){v, h[u]}; h[u] = cnt;
    	edge[++ cnt] = (Edge){u, h[v]}; h[v] = cnt;
    }
    
    int root[maxn], val[maxn];
    bool vis[maxn];
    
    int fa[maxn];
    int getfa(int x){return x == fa[x] ? x : fa[x] = getfa(fa[x]);}
    
    #define TREE 5000010
    int lc[TREE], rc[TREE], size[TREE], Size;
    
    void insert(int& rt, int l, int r, int x){
    	if(!rt)rt = ++ Size;
    	size[rt] ++;
    	if(l == r)return;
    	int mid = l + r >> 1;
    	if(x <= mid)insert(lc[rt], l, mid, x);
    	else insert(rc[rt], mid+1, r, x);
    }
    
    int merge(int x, int y){
    	if(x == 0 || y == 0)return x + y;
    	lc[x] = merge(lc[x], lc[y]);
    	rc[x] = merge(rc[x], rc[y]);
    	size[x] = size[lc[x]] + size[rc[x]];
    	return x;
    }
    
    int ask(int rt, int l, int r, int k){
    	if(l == r)return id[l];
    	int mid = l + r >> 1;
    	if(k <= size[lc[rt]])
    		return ask(lc[rt], l, mid, k);
    	k -= size[lc[rt]];
    	return ask(rc[rt], mid+1, r, k);
    }
    
    int main(){
    	scanf("%d%d", &n, &m);
    	static int w[maxn];
    	for(int i = 1; i <= n; i ++)
    	    scanf("%d", &val[i]), id[val[i]] = i;
    
    	int u, v;
    	for(int i = 1; i <= n; i ++)fa[i] = i;
    	for(int i = 1; i <= m; i ++){
    	    scanf("%d%d", &u, &v);
    		u = getfa(u), v = getfa(v);
    		fa[getfa(v)] = getfa(u);
    	}
    	
    	for(int i = 1; i <= n; i ++)
    		insert(root[getfa(i)], 1, n, val[i]);
    	int test; char cmd[2];
    	scanf("%d", &test);
    	while(test --){
    		scanf("%s", cmd);
    		if(cmd[0] == 'Q'){
    			scanf("%d%d", &u, &v), u = getfa(u);
    			if(size[root[u]] < v){puts("-1");continue;}
    			printf("%d
    ", ask(root[u], 1, n, v));
    		}
    		else{
    			scanf("%d%d", &u, &v);
    			u = getfa(u), v = getfa(v);
    			if(u == v)continue;
    			root[u] = merge(root[u], root[v]);
    			fa[getfa(v)] = getfa(u);
    		}
    	}
    	return 0;
    }
    

    [BZOJ 3702]二叉树

    #include <bits/stdc++.h>
    #define maxn 400010
    #define TREE 5000010
    using namespace std;
     
    int n, son[maxn][2], w[maxn], root[maxn];
    int cnt;
    int get_tree(){
        int x = ++ cnt, a;
        scanf("%d", &a);
        if(a)w[x] = a;
        else{
            son[x][0] = get_tree();
            son[x][1] = get_tree();
        }
        return x;
    }
     
    typedef long long ll;
    ll sum1, sum2, ans, sz[TREE];
    int lc[TREE], rc[TREE], tr_cnt;
     
    int merge(int x, int y){
        if(x == 0 || y == 0)return x + y;
        sum1 += sz[lc[x]] * sz[rc[y]];
        sum2 += sz[lc[y]] * sz[rc[x]];
        lc[x] = merge(lc[x], lc[y]);
        rc[x] = merge(rc[x], rc[y]);
        sz[x] = sz[lc[x]] + sz[rc[x]];
        return x;
    }
     
    void insert(int &rt, int l, int r, int x){
        rt = ++ tr_cnt;
        sz[rt] = 1;
        if(l == r)return;
        int mid = l + r >> 1;
        if(x <= mid) insert(lc[rt], l, mid, x);
        else insert(rc[rt], mid+1, r, x);
    }
     
    void dfs(int x){
        if(son[x][0] && son[x][1]){
            dfs(son[x][0]); dfs(son[x][1]);
            sum1 = sum2 = 0;
            root[x] = merge(root[son[x][0]], root[son[x][1]]);
            ans += min(sum1, sum2);
        }
        else insert(root[x], 1, n, w[x]);
    }
     
    int main(){
        scanf("%d", &n);
        int root = get_tree();
        dfs(root);
        printf("%lld
    ", ans);
        return 0;
    }
    

    [BZOJ 3307]雨天的尾巴

    #include <bits/stdc++.h>
    #define maxn 100010
    using namespace std;
    
    int n, m;
    
    struct Edge{
    	int to, nxt;
    }edge[maxn << 1];
    int h[maxn], cnt;
    void add(int u, int v){
    	edge[++ cnt] = (Edge){v, h[u]}; h[u] = cnt;
    	edge[++ cnt] = (Edge){u, h[v]}; h[v] = cnt;
    }
    
    int anc[maxn][20], fa[maxn], dep[maxn];
    vector<int> hav[maxn];
    
    void dfs(int u){
    	dep[u] = dep[fa[u]] + 1;
    	for(int i = h[u]; i; i = edge[i].nxt){
    		int v = edge[i].to;
    		if(v == fa[u])continue;
    		fa[v] = anc[v][0] = u;
    		dfs(v);
    	}
    }
    
    int ask_LCA(int p, int q){
    	if(dep[p] < dep[q])swap(p, q);
    	int log = 1;
    	for(; 1 << log <= dep[p]; log ++);log --;
    	for(int i = log; ~i; i --)
    	    if(dep[anc[p][i]] >= dep[q])
    	        p = anc[p][i];
    	if(p == q)return p;
    	for(int i = log; ~i; i --)
    	    if(anc[p][i] != anc[q][i])
    	        p = anc[p][i], q = anc[q][i];
    	return fa[p];
    }
    
    int ans[maxn];
    int p[maxn], c;//离散
    #define M 5000010
    int pos[M], lc[M], rc[M], mx[M], root[maxn], size;
    
    void pushup(int o){
        if(mx[lc[o]] >= mx[rc[o]]){
    		mx[o] = mx[lc[o]];
    		pos[o] = pos[lc[o]];
    	}
    	else{
            mx[o] = mx[rc[o]];
    		pos[o] = pos[rc[o]];
    	}
    }
    
    void insert(int& o, int l, int r, int val, int w){
    	if(o == 0){o = ++ size; pos[o] = l;}
    	if(l == r){mx[o] += w;return;}
    	int mid = l + r >> 1;
    	if(val <= mid)insert(lc[o], l, mid, val, w);
    	else insert(rc[o], mid+1, r, val, w);
    	pushup(o);
    }
    
    int merge(int x, int y, int l, int r){
    	if(x == 0 || y == 0)
    	    return x + y;
    	if(l == r){
    		mx[x] += mx[y];
    		pos[x] = l;
    	}
    	else{
    		int mid = l + r >> 1;
            lc[x] = merge(lc[x], lc[y], l, mid);
    		rc[x] = merge(rc[x], rc[y], mid+1, r);
    		pushup(x);
    	}return x;
    }
    
    void solve(int u){
    	for(int i = h[u]; i; i = edge[i].nxt){
    		int v = edge[i].to;
    		if(v == fa[u])continue;
    		solve(v);
    		root[u] = merge(root[u], root[v], 1, c);
    	}
    	
    	for(int i = 0; i < hav[u].size(); i ++){
    		int nw = hav[u][i], flag = nw > 0 ? 1 : -1;
    		nw = lower_bound(p + 1, p + 1 + c, abs(nw)) - p;
    	    insert(root[u], 1, c, nw, flag);
    	}
    	
    	ans[u] = mx[root[u]] > 0 ? p[pos[root[u]]] : 0;
    }
    
    int main(){
    	scanf("%d%d", &n, &m);
    	int u, v, w;
    	for(int i = 1; i < n; i ++)
    		scanf("%d%d", &u, &v), add(u, v);
    	dfs(1);
    	for(int j = 1; 1 << j <= n; j ++)
    		for(int i = 1; i <= n; i ++)
    		    anc[i][j] = anc[anc[i][j-1]][j-1];
    	
    	p[0] = 0;
    	for(int i = 1; i <= m; i ++){
    		scanf("%d%d%d", &u, &v, &w);
    		int LCA = ask_LCA(u, v);
    		hav[u].push_back(w);
    		hav[v].push_back(w);
    		hav[LCA].push_back(-w);
    		if(LCA != 1)hav[fa[LCA]].push_back(-w);
    		p[++ c] = w;
    	}
    	sort(p + 1, p + 1 + c);
    	c = unique(p + 1, p + 1 + c) - p - 1;
    
    	solve(1);
    	for(int i = 1; i <= n; i ++)
    	    printf("%d
    ", ans[i]);
    	return 0;
    }
    

      

    给时光以生命,而不是给生命以时光。
  • 相关阅读:
    swagger在线文档配置
    SpringBoot中使用Shiro和JWT做认证和鉴权
    Java web基础
    spring boot基础
    spring MVC基础
    IDEA破解(自动重置试用期)
    Linux常用jar包启动停止脚本sh命令
    Docker Desktop 容器与镜像的保存和导入
    字符串有长度限制吗
    Thyemleaf报错: Method call: Attempted to call method *** on null context object
  • 原文地址:https://www.cnblogs.com/Candyouth/p/5487069.html
Copyright © 2011-2022 走看看