Given a binary tree, flatten it to a linked list in-place.
For example,
Given
1
/
2 5
/
3 4 6
The flattened tree should look like:
1
2
3
4
5
6
Hints:
If you notice carefully in the flattened tree, each node’s right child points to the next node of a pre-order traversal
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
void flatten(TreeNode* root){
if(!root) return;
while(root){
if(root->left && root->right){
TreeNode* t = root->left;
while(t->right) t = t->right;
t->right = root->right;
root->right = NULL;
}
if(root->left){
root->right = root->left;
root->left = NULL;
}
root= root->right;
}
}
};