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  • 扩展BSGS学习笔记

    Attention

    在哈希表中查询的时候答案不能取模,可以证明是错的。

    #include <bits/stdc++.h>
    #define ll long long
    #define xx first
    #define yy second
    using namespace std;
    int a, p, b;
    inline int gcd (int m, int n) {return (!n) ? m : gcd (n, m % n);}
    unordered_map<int, int> mp;
    inline int Pow (int u, int v, int mod) {
    	int tot = 1, base = u % mod;
    	while (v) {
    		if (v & 1) {tot = 1LL * tot * base % mod;}
    		base = 1LL * base * base % mod; v /= 2;
    	}
    	return tot;
    }
    inline void solve () {
    	if (b == 1) {printf ("0
    "); return ;}
    	int d = gcd (a, p), k = 1, cnt = 0;
    	while (d > 1) {
    		if (b % d) {printf ("No Solution
    "); return ;}
    		cnt++, k = 1LL * k * (a / d) % p;
    		p /= d, b /= d;
    		if (b == k) {printf ("%d
    ", cnt); return ;}
    		d = gcd (a, p);
    	}
    	mp.clear ();
    	int sz = sqrt (p) + 1, step = Pow (a, sz, p);
    	for (int i = 1; i <= sz; ++i) {
    		k = 1LL * k * step % p;
    		if (!mp.count (k) || mp[k] > i * sz) {mp[k] = i * sz;}
    	}
    	int cdt = 1;
    	bool flag = false; int ans = INT_MAX;
    	for (int i = 0; i <= sz; ++i) {
    		if (i) {cdt = 1LL * cdt * a % p;}
    		if (mp[1LL * cdt * b % p]) {
    			int tans = mp[1LL * cdt * b % p] - i + cnt;
    //			tans = (tans % p + p) % p;
    			ans = min (ans, tans);
    			flag = true;
    		}
    	}
    	if (flag) {printf ("%d
    ", ans);return ;}
    	printf ("No Solution
    ");
    }
    int main () {
    	while (scanf ("%d%d%d", &a, &p, &b) == 3) {
    		if (a == 0 && b == 0 && p == 0) {return 0;}
    		a %= p;
    		b %= p;
    		solve ();
    	}
    	return 0;
    }
    

    这是洛谷的模板题,注释掉的地方不能要。

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  • 原文地址:https://www.cnblogs.com/ChiTongZ/p/11261896.html
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