1.计算后缀表达式
2.中缀表达式转后缀表达式
#include <cstdio> #include <cstring> #include <cctype> #include<iostream> using namespace std; //char stack char stack[25]; int top = -1; void push(char item) { stack[++top] = item; } char pop() { return stack[top--]; } //returns precedence of operators int precedence(char symbol) { switch(symbol) { case '+': case '-': return 2; break; case '*': case '/': return 3; break; case '^': return 4; break; case '(': case ')': case '#': return 1; break; } } //check whether the symbol is operator? int isOperator(char symbol) { switch(symbol) { case '+': case '-': case '*': case '/': case '^': case '(': case ')': return 1; break; default: return 0; } } //converts infix expression to postfix void convert(char infix[],char postfix[]) { int i,symbol,j = 0; stack[++top] = '#'; for(i = 0;i<strlen(infix);i++) { symbol = infix[i]; if(isOperator(symbol) == 0) { postfix[j] = symbol; j++; } else { if(symbol == '(') { push(symbol); } else { if(symbol == ')') { while(stack[top] != '(') { postfix[j] = pop(); j++; } pop(); //pop out (. } else { if(precedence(symbol)>precedence(stack[top])) { push(symbol); } else { while(precedence(symbol)<=precedence(stack[top])) { postfix[j] = pop(); j++; } push(symbol); } } } } } while(stack[top] != '#') { postfix[j] = pop(); j++; } postfix[j]='