XMU C语言程序设计实践（2）

任务一：颠倒的世界

 

小明最近突然喜欢倒着写字，写出来的句子全是颠倒的，也就是把一句话里的字符全都逆序写，譬如“I Love This Game！”，他就偏偏要写成“!emaG sihT evoL I”弄的小华同他Email交流都很难受。请你帮助小华解决这个问题，将输入的字符串全都还原成本来的面目。

 

任务1要求：

利用main函数带参数的功能，编写程序，将命令行中的字符串全部逆序显示出来。例如编写的可执行文件为go.exe 那么运行 go !emaG sihT evoL I 时，显示出I Love This Game！

任务二：时间转换

由于工作原因，小明常常需要签署文件日期，但他比较偷懒，都用阿拉伯数字签署，譬如3.8表示三月八日，7.12表示七月十二日。最近公司改组成外资企业，主管要求将所有的日期全部更改为英文表示，一来同国际接轨，二来也不容易篡改，譬如将3.8表示为March the eighth 面对这么多的日期，小明犯愁了，他英文不好，那么多的英文单词他记不住。而且小明还是个马大哈，有时候居然会签出3.32（三月三十二日）这样的日期，为了避免被上司责备，趁着这次机会也赶快一并修改。请你帮助小明完成这个任务。

 

任务2要求：

利用main函数带参数的功能，编写程序，将命令行中的字符串翻译成英文表示，每行显示一个日期，同时需检查日期表示是否有误，如有误，请给出提示。例如：编写的可执行文件为go.exe 那么运行go  3.8  5.5  4.38 时显示

March the eighth

May the fifth

Error

任务三：时间转换(续)

小明觉得这么一点点的手工输入还是有点麻烦，他把需要翻译的日期都整理到文本文件in.txt中，请你帮助小明，将其中的内容翻译完毕后保存到文本文件out.txt中，便于他统一处理。

任务3要求：翻译过程同任务2，将结果保存至文件out.txt中

 

第一题：

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define max(a,b) ((a)>(b)?(a):(b))
#define min(a,b) ((a)<(b)?(a):(b))
#define abs(a) ((a)>0?(a):(-(a)))
#define sqr(a) ((a)*(a))
#define swap(a,b) (a)^=(b),(b)^=(a),(a)^=(b)
#define eps 1e-8
#define MAX 0x7f7f7f7f
#define N 104
int a[N];
int main(int argc,char* argv[])
{
    int i,j,k;
    for(i=argc-1;i>0;i--)
    {
        for(j=strlen(argv[i])-1;j>=0;j--)
            putchar(argv[i][j]);
        printf(" ");
    }
    puts("");
    return 0;
}
/*
Q:xxx111222inDebug222 !emaG sihT evoL I
*/

第二题：

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define max(a,b) ((a)>(b)?(a):(b))
#define min(a,b) ((a)<(b)?(a):(b))
#define abs(a) ((a)>0?(a):(-(a)))
#define sqr(a) ((a)*(a))
#define swap(a,b) (a)^=(b),(b)^=(a),(a)^=(b)
#define eps 1e-8
#define MAX 0x7f7f7f7f
#define N 104
int m,d;
int mon[]={0,31,28,31,30,31,30,31,31,30,31,30,31};
char *M[]={"","January","February","March","April","May","June","July","August","September","October","November","December"};
char *D[]={"","first","second","third","fourth","fifth","sixth","seventh","eighth","ninth","tenth","eleventh","twelfth","thirteenth","fourteenth","fifteenth","sixteenth","seventeenth","eighteenth","nineteenth","twentieth","twenty-first","twenty-second","twenty-third","twenty-fourth","twenty-fifth","twenty-sixth","twenty-seventh","twenty-eighth","twenty-ninth","thirtieth","thirty-first"};
void work(char s[])
{
    int i;
    m=d=0;
    if(s[2]=='.')
    {
        m=(s[0]-'0')*10+s[1]-'0';
        i=3;
    }
    else if(s[1]=='.')
    {
        m=s[0]-'0';
        i=2;
    }
    for(;i<strlen(s);i++)
        d=d*10+s[i]-'0';
}
int main(int argc,char * argv[])
{
    int i,j,k;
    for(i=1;i<argc;i++)
    {
        work(argv[i]);
        if(d>mon[m] || d<1 || m>12 ||m<1)puts("Error");
        else printf("%s the %s",*(M+m),*(D+d));
        puts("");
    }
    return 0;
}
/*
Q:xxx111222inDebug222 3.8 5.5 4.38
*/

第三题：

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define max(a,b) ((a)>(b)?(a):(b))
#define min(a,b) ((a)<(b)?(a):(b))
#define abs(a) ((a)>0?(a):(-(a)))
#define sqr(a) ((a)*(a))
#define swap(a,b) (a)^=(b),(b)^=(a),(a)^=(b)
#define eps 1e-8
#define MAX 0x7f7f7f7f
#define N 1004
int m,d;
int mon[]={0,31,28,31,30,31,30,31,31,30,31,30,31};
char argv[N];
char *M[]={"","January","February","March","April","May","June","July","August","September","October","November","December"};
char *D[]={"","first","second","third","fourth","fifth","sixth","seventh","eighth","ninth","tenth","eleventh","twelfth","thirteenth","fourteenth","fifteenth","sixteenth","seventeenth","eighteenth","nineteenth","twentieth","twenty-first","twenty-second","twenty-third","twenty-fourth","twenty-fifth","twenty-sixth","twenty-seventh","twenty-eighth","twenty-ninth","thirtieth","thirty-first"};
void work(char s[])
{
    int i;
    m=d=0;
    if(s[2]=='.')
    {
        m=(s[0]-'0')*10+s[1]-'0';
        i=3;
    }
    else if(s[1]=='.')
    {
        m=s[0]-'0';
        i=2;
    }
    for(;i<strlen(s);i++)
        d=d*10+s[i]-'0';
}
int main()
{
    FILE *fp1=fopen("Q:\xxx\111\111\in.txt","r"),*fp=fopen("Q:\xxx\111\111\out.txt","w");
    int i,j,k;
    while(~fscanf(fp1,"%s",argv))
    {
        work(argv);
        if(d>mon[m] || d<1 || m>12 ||m<1)fputs("Error
",fp);
        else fprintf(fp,"%s the %s
",*(M+m),*(D+d));
    }
    fclose(fp1);
    fclose(fp);
    return 0;
}
/*
Q:xxx111111inDebug111 3.8 5.5 4.38 13.1 1.32 1.0 2.29 115123 3.31
*/