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  • POJ 2993 Emag eht htiw Em Pleh 模拟

    http://poj.org/problem?id=2993

    模拟大法好。

     1 #include<iostream>
     2 #include<cstdio>
     3 #include<cstring>
     4 using namespace std;
     5 char q[10],w[100];
     6 char e[10],r[100];
     7 char white[12]= {'K','Q','R','B','N','P'};
     8 char black[12]= {'k','q','r','b','n','p'};
     9 char map1[18][35];
    10 int s1,s2;
    11 int main()
    12 {
    13     int i,j;
    14     for(i=1; i<=17; i++)                    
    15         for(j=1; j<=33; j++)
    16         {
    17             if(i%2==1&&j%4==1)
    18                 map1[i][j]='+';
    19             else  if(i%2==1)
    20                 map1[i][j]='-';
    21             else  if(i%2==0&&j%4==1)
    22                 map1[i][j]='|';
    23             else if(i%4==2&&(double)(j%8)/4<=1&&j%8!=0)
    24                 map1[i][j]='.';
    25             else if(i%4==0&&((double)(j%8)/4>1||j%8==0))
    26                 map1[i][j]='.';
    27             else
    28                 map1[i][j]=':';
    29         }
    30     for(int k=1; k<=2; k++)        
    31     {
    32         scanf("%s%s",q,w);
    33         s1=strlen(w);
    34         if(q[0]=='W')
    35         {
    36             for(i=0; i<=5; i++)
    37                 for(j=0; j<=s1; j++)
    38                 {
    39                     if(w[j]==white[i])
    40                         map1[2*(9-w[j+2]+'0')][4*(w[j+1]-'a')+3]=white[i];
    41                     if(w[j]==','&&w[j+1]>96)
    42                         map1[2*(9-w[j+2]+'0')][4*(w[j+1]-'a')+3]='P';
    43                 }
    44         }
    45         if(q[0]=='B')
    46         {
    47             for(i=0; i<=5; i++)
    48                 for(j=0; j<=s1; j++)
    49                 {
    50                     if(w[j]==white[i])
    51                         map1[2*(9-w[j+2]+'0')][4*(w[j+1]-'a')+3]=black[i];
    52                     if(w[j]==','&&w[j+1]>96)
    53                         map1[2*(9-w[j+2]+'0')][4*(w[j+1]-'a')+3]='p';
    54                 }
    55         }
    56     }
    57     for(i=1; i<=17; i++)
    58     {
    59         for(j=1; j<=33; j++)
    60             cout<<map1[i][j];
    61         cout<<endl;
    62     }
    63     return 0;
    64 }
    View Code
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    【题解】LibreOJ #6279. 数列分块入门 3
  • 原文地址:https://www.cnblogs.com/CrazyBaby/p/5689758.html
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