Given an array nums
, write a function to move all 0
's to the end of it while maintaining the relative order of the non-zero elements.
For example, given nums = [0, 1, 0, 3, 12]
, after calling your function, nums
should be [1, 3, 12, 0, 0]
.
Note:
- You must do this in-place without making a copy of the array.
- Minimize the total number of operations.
Credits:
Special thanks to @jianchao.li.fighter for adding this problem and creating all test cases.
思路:整个过程是个不停交换的过程,把非0的数和 0 交换位置。时间要求为O(n),代码如下
class Solution { public void moveZeroes(int[] nums) { int position = 0; //把非0的数换到这位置上 for (int i=0;i<nums.length;i++){ if (nums[i]!=0){ int tmp = nums[position]; nums[position++] = nums[i]; nums[i] = tmp; } } } }