zoukankan      html  css  js  c++  java
  • poj 1562 Oil Deposits

    Oil Deposits
    Time Limit: 1000MS   Memory Limit: 10000K
    Total Submissions: 13505   Accepted: 7345

    Description

    The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square plots. It then analyzes each plot separately, using sensing equipment to determine whether or not the plot contains oil. A plot containing oil is called a pocket. If two pockets are adjacent, then they are part of the same oil deposit. Oil deposits can be quite large and may contain numerous pockets. Your job is to determine how many different oil deposits are contained in a grid.

    Input

    The input contains one or more grids. Each grid begins with a line containing m and n, the number of rows and columns in the grid, separated by a single space. If m = 0 it signals the end of the input; otherwise 1 <= m <= 100 and 1 <= n <= 100. Following this are m lines of n characters each (not counting the end-of-line characters). Each character corresponds to one plot, and is either `*', representing the absence of oil, or `@', representing an oil pocket. 

    Output

    are adjacent horizontally, vertically, or diagonally. An oil deposit will not contain more than 100 pockets.

    Sample Input

    1 1
    *
    3 5
    *@*@*
    **@**
    *@*@*
    1 8
    @@****@*
    5 5 
    ****@
    *@@*@
    *@**@
    @@@*@
    @@**@
    0 0

    Sample Output

    0
    1
    2
    2
    

    Source

     
     
    分析:
    只有map[i][j]==0,该位置是新的oil deposit。然后广搜。
     1 #include<iostream>
     2 #include<queue>
     3 #include<cstdio>
     4 #include<cstring>
     5 using namespace std;
     6 int m,n;
     7 short map[105][105];
     8 short dir[8][2]={{-1,-1},{-1,0},{-1,1},{0,1},{1,1},{1,0},{1,-1},{0,-1}};
     9 bool check(int x,int y){
    10     if(x<0||x>=m||y<0||y>=n||map[x][y])
    11     return false;
    12     return true;
    13 }
    14 int main(){
    15     while(scanf("%d%d",&m,&n)&&m!=0&&n!=0){
    16         memset(map,0,sizeof(map));
    17         int i,j;
    18         for(i=0;i<m;i++){
    19             for(j=0;j<n;j++){
    20                 char c;
    21                 cin>>c;
    22                 if(c=='*'){
    23                     map[i][j]=-1;
    24                 }
    25                 else{
    26                     map[i][j]=0;
    27                 }
    28             }
    29         }
    30         //cout<<1<<endl;
    31         /*for(i=0;i<m;i++){
    32             for(j=0;j<n;j++){
    33                 cout<<map[i][j]<<endl;
    34             }
    35         }*/
    36         int count=0;
    37         for(i=0;i<m;i++){
    38             for(j=0;j<n;j++){
    39                 if(map[i][j]==0){
    40                 queue<int> q;
    41                 q.push(i*100+j);
    42                 map[i][j]=++count;
    43                 while(!q.empty()){
    44                     short x=q.front()/100;
    45                     short y=q.front()%100;
    46                     q.pop();
    47                     int k;
    48                     for(k=0;k<8;k++){
    49                         short xx=x+dir[k][0];
    50                         short yy=y+dir[k][1];
    51                         if(check(xx,yy)){
    52                             q.push(xx*100+yy);
    53                             map[xx][yy]=map[x][y];
    54                         }
    55                     }
    56                 }    
    57                 }
    58             }
    59         }
    60         /*for(i=0;i<m;i++){
    61             for(j=0;j<n;j++){
    62                 cout<<map[i][j]<<endl;
    63             }
    64         }*/
    65         cout<<count<<endl;
    66     }
    67     return 0;
    68 }
  • 相关阅读:
    第3天:视图提取请求参数和响应对象
    第2天:Django路由与视图
    第1天:Django框架简介与工程创建
    Jenkins多选项框使用
    备份Kylin的Metadata
    前台传值 后台接受乱码
    查询表的列名,字符类型
    html div隐藏后取消所占的空位
    bootstrap 利用jquery 添加disabled属性
    bootstrap datetimepicker 复选可删除,可规定指定日期不可选
  • 原文地址:https://www.cnblogs.com/Deribs4/p/4282987.html
Copyright © 2011-2022 走看看