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  • 九度oj 1002 Grading 2011年浙江大学计算机及软件工程研究生机试真题

     1 #include<iostream>
     2 #include<queue>
     3 #include<cstdio>
     4 #include<cstring>
     5 #include<cmath>
     6 #include<algorithm>
     7 using namespace std;
     8 int map[15][15];
     9 int main(){
    10     int P,T,G1,G2,G3,GJ;
    11     while(cin>>P>>T>>G1>>G2>>G3>>GJ){
    12         if(abs(G1-G2)<=T){
    13             printf("%.1lf
    ",1.0*(G1+G2)/2);
    14         }
    15         else{
    16             int m1=abs(G1-G3);
    17             int m2=abs(G3-G2);
    18             if(m1<=T&&m2<=T){
    19                 int max=G1>G2?G1:G2;
    20                 max=max>G3?max:G3;
    21                 printf("%.1lf
    ",max*1.0);
    22             }
    23             else{
    24                 if(m1<=T||m2<=T){
    25                     if(m1>m2){
    26                         printf("%.1lf
    ",(G3+G2)*1.0/2);
    27                     }
    28                     else{
    29                         printf("%.1lf
    ",(G3+G1)*1.0/2);
    30                     }
    31                 }
    32                 else{
    33                     printf("%.1lf
    ",GJ*1.0);
    34                 }
    35             }
    36         }
    37     }
    38     return 0;
    39 }

    时间限制:1 秒

    内存限制:32 兆

    特殊判题:

    提交:16128

    解决:4162

    题目描述:

        Grading hundreds of thousands of Graduate Entrance Exams is a hard work. It is even harder to design a process to make the results as fair as possible. One way is to assign each exam problem to 3 independent experts. If they do not agree to each other, a judge is invited to make the final decision. Now you are asked to write a program to help this process.
        For each problem, there is a full-mark P and a tolerance T(<P) given. The grading rules are:
        • A problem will first be assigned to 2 experts, to obtain G1 and G2. If the difference is within the tolerance, that is, if |G1 - G2| ≤ T, this problem's grade will be the average of G1 and G2.
        • If the difference exceeds T, the 3rd expert will give G3.
        • If G3 is within the tolerance with either G1 or G2, but NOT both, then this problem's grade will be the average of G3 and the closest grade.
        • If G3 is within the tolerance with both G1 and G2, then this problem's grade will be the maximum of the three grades.
        • If G3 is within the tolerance with neither G1 nor G2, a judge will give the final grade GJ.

    输入:

        Each input file may contain more than one test case.
        Each case occupies a line containing six positive integers: P, T, G1, G2, G3, and GJ, as described in the problem. It is guaranteed that all the grades are valid, that is, in the interval [0, P].

    输出:

        For each test case you should output the final grade of the problem in a line. The answer must be accurate to 1 decimal place.

    样例输入:
    20 2 15 13 10 18
    样例输出:
    14.0
    来源:
    2011年浙江大学计算机及软件工程研究生机试真题
    分析:
    读懂题意即可
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  • 原文地址:https://www.cnblogs.com/Deribs4/p/4288875.html
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