pat1058. A+B in Hogwarts (20)

1058. A+B in Hogwarts (20)

时间限制

50 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 10⁷], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28

---

提交代码

#include<cstdio>
#include<stack>
#include<cstring>
#include<iostream>
#include<stack>
#include<set>
#include<map>
using namespace std;
int dight[3];
int main(){
    //freopen("D:\INPUT.txt","r",stdin);
    int a,b,c;
    scanf("%d.%d.%d",&a,&b,&c);
    scanf("%d.%d.%d",&dight[0],&dight[1],&dight[2]);
    dight[0]+=a;
    dight[1]+=b;
    dight[2]+=c;
    dight[1]+=dight[2]/29;
    dight[2]%=29;
    dight[0]+=dight[1]/17;
    dight[1]%=17;
    printf("%d.%d.%d
",dight[0],dight[1],dight[2]);
    return 0;
}