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  • Leetcode 235. Lowest Common Ancestor of a Binary Search Tree

    235. Lowest Common Ancestor of a Binary Search Tree

    Total Accepted: 77021 Total Submissions: 205265 Difficulty: Easy

    Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.

    According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself).”

    _______6______
           /              
        ___2__          ___8__
       /              /      
       0      _4       7       9
             /  
             3   5

    For example, the lowest common ancestor (LCA) of nodes 2 and 8 is 6. Another example is LCA of nodes 2 and 4 is 2, since a node can be a descendant of itself according to the LCA definition.

    思路:

    二叉排序树(Binary Sort Tree)又称二叉查找(搜索)树(Binary Search Tree)。其定义为:二叉排序树或者是空树,或者是满足如下性质的二叉树:
    ①若它的左子树非空,则左子树上所有结点的值均小于根结点的值;
    ②若它的右子树非空,则右子树上所有结点的值均大于根结点的值;
    ③左、右子树本身又各是一棵二叉排序树。

    代码:
    迭代:

     1 /**
     2  * Definition for a binary tree node.
     3  * struct TreeNode {
     4  *     int val;
     5  *     TreeNode *left;
     6  *     TreeNode *right;
     7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
     8  * };
     9  */
    10 class Solution {
    11 public:
    12     TreeNode* lowestCommonAncestor(TreeNode* root, TreeNode* p, TreeNode* q) {
    13         while(true){
    14             if(root->val>p->val&&root->val>q->val){
    15                 root=root->left;
    16                 continue;
    17             }
    18             if(root->val<p->val&&root->val<q->val){
    19                 root=root->right;
    20                 continue;
    21             }
    22             return root;
    23         }
    24     }
    25 };

    递归:

    1 class Solution {
    2 public:
    3     TreeNode* lowestCommonAncestor(TreeNode* root, TreeNode* p, TreeNode* q) {
    4         if(root->val>p->val&&root->val>q->val) return lowestCommonAncestor(root->left,p,q);
    5         if(root->val<p->val&&root->val<q->val) return lowestCommonAncestor(root->right,p,q);
    6         return root;
    7     }
    8 };

    还有另外1题,和这题相似:Leetcode 236. Lowest Common Ancestor of a Binary Tree

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  • 原文地址:https://www.cnblogs.com/Deribs4/p/5626215.html
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