zoukankan      html  css  js  c++  java
  • UVa1587.Digit Counting

    题目连接:http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=247&page=show_problem&problem=3666

    13764622 1225 Digit Counting Accepted C++11 0.035 2014-06-18 07:44:02

     

    1225 - Digit Counting

    Time limit: 3.000 seconds

    Trung is bored with his mathematics homeworks. He takes a piece of chalk and starts writing a sequence of consecutive integers starting with 1 to N (1 < N < 10000) . After that, he counts the number of times each digit (0 to 9) appears in the sequence. For example, with N = 13 , the sequence is:

    12345678910111213

    In this sequence, 0 appears once, 1 appears 6 times, 2 appears 2 times, 3 appears 3 times, and each digit from 4 to 9 appears once. After playing for a while, Trung gets bored again. He now wants to write a program to do this for him. Your task is to help him with writing this program.

    Input 

    The input file consists of several data sets. The first line of the input file contains the number of data sets which is a positive integer and is not bigger than 20. The following lines describe the data sets.

    For each test case, there is one single line containing the number N .

    Output 

    For each test case, write sequentially in one line the number of digit 0, 1,...9 separated by a space.

    Sample Input 

    2 
    3 
    13
    

    Sample Output 

    0 1 1 1 0 0 0 0 0 0 
    1 6 2 2 1 1 1 1 1 1



    题目大意:输入一个数N,然后会 123456789……N 这么一个数,算出其中0~9数字出现的个数。
    解题思路:题目不难,字符串处理就能轻松解决。主意输出不要有多的空格就ok。

     1 #include <iostream>
     2 #include <cstring>
     3 #include <cstdio>
     4 #include <cctype>
     5 #include <algorithm>
     6 #include <numeric>
     7 #include <string>
     8 #include <sstream>
     9 using namespace std;
    10 
    11 int main() {
    12     int l, maxx_int; cin >> l;
    13     string maxx_str;
    14     int tab[10];
    15     while(l--) {
    16         cin >> maxx_int;
    17         memset(tab, 0, sizeof(tab));
    18         for(int i = 1; i <= maxx_int; i++) {
    19             stringstream ss;
    20             ss << i; ss >> maxx_str;
    21             for(int j = 0; j < maxx_str.size(); j++) {
    22                 tab[maxx_str[j] - '0'] ++;
    23             }
    24         }
    25         for(int i = 0; i < 10; i++) {
    26             if(i == 0) {
    27                 cout << tab[i];
    28             } else {
    29 
    30                 cout << " " << tab[i];
    31             }
    32         }
    33         cout << endl;
    34         //cout << maxx_str << endl;
    35     }
    36     return 0;
    37 }
    AC代码
  • 相关阅读:
    Algorand算法实现(一)
    什么是跨链?为什么要跨链?
    Web配置简单记录(多更新)
    Web前端常用调优
    回文素数
    postman接口请求快速新建
    两台虚拟机如何ping通
    vue动态改变标题
    js正则匹配版本号V1.0.0
    js获取年月日星期时分秒
  • 原文地址:https://www.cnblogs.com/Destiny-Gem/p/3795060.html
Copyright © 2011-2022 走看看