C#限制MDI子窗体重复打开——C#判断窗体是否已经打开 多种方法 20120626更新

private bool HaveOpened(Form 父窗体, string 子窗体Name)
        {
            //查看窗口是否已经被打开
            bool bReturn = true;
            for (int i = 0; i < 父窗体.MdiChildren.Length; i++)
            {
                if (父窗体.MdiChildren[i].Name == 子窗体Name)
                {
                    父窗体.MdiChildren[i].BringToFront();
                    bReturn = false;
                    break;
                }
            }
            return bReturn;
        }

 

 

打开窗体时调用上述方法：

 

Form1 f1=new Form();
if (HaveOpened(父窗体, "子窗体Name"))
            {
                f1.MdiParent = 父窗体;
                f1.Show();
            }

通过窗口名判断是否已经打开窗口,如此做的好处就是一个窗体通过不同的Name打开多个这个窗口

比如说不同的模块打开不同的Mdi父窗体.但相同的Name只能打开一个

/// <summary>
        /// 判断是否打开Mdi的窗口,如打开则得到窗口
        /// </summary>
        /// <param name="asFormName"></param>
        /// <returns></returns>
        public Form CheckMdiFormIsOpen(string asFormName)
        {
            Form form = null;
            foreach (Form frm in Application.OpenForms)
            {
                if (frm.Name == asFormName)
                {
                    form = frm;
                    break;
                }
            }
            return form;
        }

private bool ContainMDIChild(string childTypeString)
        {
            Form form = null;
            foreach (Form form2 in base.MdiChildren)
            {
                if (form2.GetType().ToString() == childTypeString)
                {
                    form = form2;
                    break;
                }
            }
            if (form != null)
            {
                //form.TopMost = true;
                form.Show();
                form.Focus();
                return true;
            }
            return false;
        }

        private bool ContainChild(string childTypeString)
        {
            Form form = null;
            foreach (Form form2 in Application.OpenForms)
            {
                if (form2.GetType().ToString() == childTypeString)
                {
                    form = form2;
                    break;
                }
            }
            if (form != null)
            {
                //form.TopMost = true;
                form.Show();
                form.Focus();
                return true;
            }
            return false;
        }