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  • MySQL-数据操作-增删改查

    1.增加:

    insert into 表 (列名,列名...) values (值,值,值...)
    insert into 表 (列名,列名...) values (值,值,值...),(值,值,值...)
    insert into 表 (列名,列名...) select (列名,列名...) from

    2.删除:

    delete fromdelete fromwhere id=1 and name='alex'

    3.修改:

    updateset name = 'alex' where id>1

    4.查询:

    select * fromselect * fromwhere id > 1
    select nid,name,gender as gg fromwhere id > 1

    5.补充

    a、条件
        select * fromwhere id > 1 and name != 'alex' and num = 12;
     
        select * fromwhere id between 5 and 16;
     
        select * fromwhere id in (11,22,33)
        select * fromwhere id not in (11,22,33)
        select * fromwhere id in (select nid from 表)
     
    b、通配符
        select * fromwhere name like 'ale%'  - ale开头的所有(多个字符串)
        select * fromwhere name like 'ale_'  - ale开头的所有(一个字符)
     
    c、限制
        select * from 表 limit 5;            - 前5行
        select * from 表 limit 4,5;          - 从第4行开始的5行
        select * from 表 limit 5 offset 4    - 从第4行开始的5行
     
    d、排序
        select * fromorder byasc              - 根据 “列” 从小到大排列
        select * fromorder bydesc             - 根据 “列” 从大到小排列
        select * fromorder by 列1 desc,列2 asc    - 根据 “列1” 从大到小排列,如果相同则按列2从小到大排序
     
    e、分组
        select num fromgroup by num
        select num,nid fromgroup by num,nid
        select num,nid fromwhere nid > 10 group by num,nid order nid desc
        select num,nid,count(*),sum(score),max(score),min(score) fromgroup by num,nid
     
        select num fromgroup by num having max(id) > 10
     
        特别的:group by 必须在where之后,order by之前
     
    f、连表
        无对应关系则不显示
        select A.num, A.name, B.name
        from A,B
        Where A.nid = B.nid
     
        无对应关系则不显示
        select A.num, A.name, B.name
        from A inner join B
        on A.nid = B.nid
     
        A表所有显示,如果B中无对应关系,则值为null
        select A.num, A.name, B.name
        from A left join B
        on A.nid = B.nid
     
        B表所有显示,如果B中无对应关系,则值为null
        select A.num, A.name, B.name
        from A right join B
        on A.nid = B.nid
     
    g、组合
        组合,自动处理重合
        select nickname
        from A
        union
        select name
        from B
     
        组合,不处理重合
        select nickname
        from A
        union all
        select name
        from B
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  • 原文地址:https://www.cnblogs.com/DragonFire/p/6994666.html
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