题目链接
https://www.nowcoder.com/acm/contest/70/A
思路
暴力每一个子串 用 MAP 标记一下 然后 最后 遍历一遍 MAP 找出 出现次数最多 并且 字典序最小的那个
AC代码
#include <cstdio>
#include <cstring>
#include <ctype.h>
#include <cstdlib>
#include <iostream>
#include <algorithm>
#include <cmath>
#include <deque>
#include <vector>
#include <queue>
#include <string>
#include <map>
#include <stack>
#include <set>
#include <numeric>
#include <sstream>
#include <iomanip>
using namespace std;
typedef long long LL;
const double PI = 3.14159265358979323846264338327;
const double E = 2.718281828459;
const double eps = 1e-6;
const int MAXN = 0x3f3f3f3f;
const int MINN = 0xc0c0c0c0;
const int maxn = 1e5 + 5;
const int MOD = 1e9 + 7;
int main()
{
string s, temp;
cin >> s;
map <string, int> m;
m.clear();
int len = s.size();
for (int i = 0; i < len; i++)
{
if (s[i] == '4' || s[i] == '7')
{
temp.clear();
for (int j = i; j < len; j++)
{
temp += s[j];
m[temp]++;
}
}
}
map <string, int>::iterator it;
int Max = -1;
for (it = m.begin(); it != m.end(); it++)
{
if (it -> second > Max)
{
temp = it -> first;
Max = it -> second;
}
}
if (Max != -1)
cout << temp << endl;
else
cout << -1 << endl;
}