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  • LeetCode Number of Segments in a String

    原题链接在这里:https://leetcode.com/problems/number-of-segments-in-a-string/

    题目:

    Count the number of segments in a string, where a segment is defined to be a contiguous sequence of non-space characters.

    Please note that the string does not contain any non-printable characters.

    Example:

    Input: "Hello, my name is John"
    Output: 5

    题解:

    使用trim 和 split的到结果. 

    s = ""时split后的array length 是1. 

    s开始有空格, e.g. " bc", split后长度是2, ["", "bc"]. 但结束为空格, e.g. "bc ", split 后长度为1, ["bc"].

    Time Complexity: O(n), n = s.length(), split用时.

    Space: O(n), split后array大小.

    AC Java:

    1 public class Solution {
    2     public int countSegments(String s) {
    3         String trimS = s.trim();
    4         if(trimS.length() == 0){
    5             return 0;
    6         }
    7         return trimS.split("\s+").length;
    8     }
    9 }

    当前char不等于' '时,要么当前index为0或者前一位char等于' ', res++.

    Time Complexity: O(n). Space: O(1).

    AC Java:

     1 public class Solution {
     2     public int countSegments(String s) {
     3         int res = 0;
     4         for(int i = 0; i<s.length(); i++){
     5             if(s.charAt(i) != ' ' && (i == 0 || s.charAt(i-1) == ' ')){
     6                 res++;
     7             }
     8         }
     9         return res;
    10     }
    11 }
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  • 原文地址:https://www.cnblogs.com/Dylan-Java-NYC/p/6296471.html
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