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  • 平面上给定n条线段,找出一个点,使这个点到这n条线段的距离和最小。

    题目:平面上给定n条线段,找出一个点,使这个点到这n条线段的距离和最小。

    源码如下:

     1 #include <iostream>  
     2 #include <string.h>  
     3 #include <stdlib.h>  
     4 #include <stdio.h>  
     5 #include <time.h>  
     6 #include <math.h>  
     7   
     8 #define N 1005  
     9 #define eps 1e-8     //搜索停止条件阀值  
    10 #define INF 1e99       
    11 #define delta 0.98   //温度下降速度  
    12 #define T 100        //初始温度  
    13   
    14 using namespace std;  
    15   
    16 int dx[4] = {0, 0, -1, 1};  
    17 int dy[4] = {-1, 1, 0, 0};  //上下左右四个方向  
    18   
    19 struct Point  
    20 {  
    21     double x, y;  
    22 };  
    23   
    24 Point s[N], t[N];  
    25   
    26 double cross(Point A, Point B, Point C)    
    27 {    
    28     return (B.x - A.x) * (C.y - A.y) - (B.y - A.y) * (C.x - A.x);    
    29 }    
    30   
    31 double multi(Point A, Point B, Point C)    
    32 {    
    33     return (B.x - A.x) * (C.x - A.x) + (B.y - A.y) * (C.y - A.y);    
    34 }    
    35   
    36 double dist(Point A, Point B)  
    37 {  
    38     return sqrt((A.x - B.x) * (A.x - B.x) + (A.y - B.y) * (A.y - B.y));  
    39 }  
    40   
    41 double GetDist(Point A, Point B, Point C)    
    42 {    
    43     if(dist(A, B) < eps) return dist(B, C);    
    44     if(multi(A, B, C) < -eps) return dist(A, C);    
    45     if(multi(B, A, C) < -eps) return dist(B, C);    
    46     return fabs(cross(A, B, C) / dist(A, B));    
    47 }    
    48   
    49 double GetSum(Point s[], Point t[], int n, Point o)  
    50 {  
    51     double ans = 0;  
    52     while(n--)  
    53         ans += GetDist(s[n], t[n], o);  
    54     return ans;  
    55 }  
    56   
    57 double Search(Point s[], Point t[], int n, Point &o)  
    58 {  
    59     o = s[0];      
    60     double tem = T;        
    61     double ans = INF;  
    62     while(tem > eps)  
    63     {  
    64         bool flag = 1;  
    65         while(flag)  
    66         {  
    67             flag = 0;  
    68             for(int i = 0; i < 4; i++)    //上下左右四个方向  
    69             {  
    70                 Point z;  
    71                 z.x = o.x + dx[i] * tem;  
    72                 z.y = o.y + dy[i] * tem;  
    73                 double tp = GetSum(s, t, n, z);  
    74                 if(ans > tp)  
    75                 {  
    76                     ans = tp;  
    77                     o = z;  
    78                     flag = 1;  
    79                 }  
    80             }  
    81         }  
    82         tem *= delta;  
    83     }  
    84     return ans;  
    85 }  
    86   
    87 int main()  
    88 {  
    89     int n;  
    90     while(scanf("%d", &n) != EOF)  
    91     {  
    92         for(int i = 0; i < n; i++)  
    93             scanf("%lf %lf %lf %lf", &s[i].x, &s[i].y, &t[i].x, &t[i].y);  
    94         Point o;  
    95         double ans = Search(s, t, n, o);  
    96         printf("%.1lf %.1lf %.1lf
    ", o.x, o.y, ans);    
    97     }  
    98     return 0;  
    99 }  
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  • 原文地址:https://www.cnblogs.com/ECJTUACM-873284962/p/8468780.html
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