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  • 不错的sql面试题

    Student(S#,Sname,Sage,Ssex) 学生表
    Course(C#,Cname,T#) 课程表
    SC(S#,C#,score) 成绩表
    Teacher(T#,Tname) 教师表
    问题:
    1、查询“001”课程比“002”课程成绩高的所有学生的学号;
      select a.S# from (select s#,score from SC where C#='001') a,(select s#,score
      from SC where C#='002') b
      where a.score>b.score and a.s#=b.s#;
    2、查询平均成绩大于60分的同学的学号和平均成绩;
        select S#,avg(score)
        from sc
        group by S# having avg(score) >60;
    3、查询所有同学的学号、姓名、选课数、总成绩;
      select Student.S#,Student.Sname,count(SC.C#),sum(score)
      from Student left Outer join SC on Student.S#=SC.S#
      group by Student.S#,Sname
    4、查询姓“李”的老师的个数;
      select count(distinct(Tname))
      from Teacher
      where Tname like '李%';
    5、查询没学过“叶平”老师课的同学的学号、姓名;
        select Student.S#,Student.Sname
        from Student  
        where S# not in (select distinct( SC.S#) from SC,Course,Teacher where  SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='叶平');
    6、查询学过“001”并且也学过编号“002”课程的同学的学号、姓名;
      select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#='001'and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#='002');
    7、查询学过“叶平”老师所教的所有课的同学的学号、姓名;
      select S#,Sname
      from Student
      where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='叶平' group by S# having count(SC.C#)=(select count(C#) from Course,Teacher  where Teacher.T#=Course.T# and Tname='叶平'));
    8、查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名;
      Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') score2
      from Student,SC where Student.S#=SC.S# and C#='001') S_2 where score2 60);
    10、查询没有学全所有课的同学的学号、姓名;
        select Student.S#,Student.Sname
        from Student,SC
        where Student.S#=SC.S# group by  Student.S#,Student.Sname having count(C#) =60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分数
        FROM SC T,Course
        where t.C#=course.C#
        GROUP BY t.C#
        ORDER BY 100 * SUM(CASE WHEN  isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC
    20、查询如下课程平均成绩和及格率的百分数(用"1行"显示): 企业管理(001),马克思(002),OO&UML (003),数据库(004)
        SELECT SUM(CASE WHEN C# ='001' THEN score ELSE 0 END)/SUM(CASE C# WHEN '001' THEN 1 ELSE 0 END) AS 企业管理平均分
            ,100 * SUM(CASE WHEN C# = '001' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '001' THEN 1 ELSE 0 END) AS 企业管理及格百分数
            ,SUM(CASE WHEN C# = '002' THEN score ELSE 0 END)/SUM(CASE C# WHEN '002' THEN 1 ELSE 0 END) AS 马克思平均分
            ,100 * SUM(CASE WHEN C# = '002' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '002' THEN 1 ELSE 0 END) AS 马克思及格百分数
            ,SUM(CASE WHEN C# = '003' THEN score ELSE 0 END)/SUM(CASE C# WHEN '003' THEN 1 ELSE 0 END) AS UML平均分
            ,100 * SUM(CASE WHEN C# = '003' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '003' THEN 1 ELSE 0 END) AS UML及格百分数
            ,SUM(CASE WHEN C# = '004' THEN score ELSE 0 END)/SUM(CASE C# WHEN '004' THEN 1 ELSE 0 END) AS 数据库平均分
            ,100 * SUM(CASE WHEN C# = '004' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '004' THEN 1 ELSE 0 END) AS 数据库及格百分数
      FROM SC

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  • 原文地址:https://www.cnblogs.com/EWall/p/2031616.html
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