Lintcode: Fizz Buzz

Given number n. Print number from 1 to n. But:

when number is divided by 3, print fizz;

when number is divided by 5, print buzz;

when number is divided by both 3 and 5, print fizz buzz.

Example
If n=15, you should return ["1", "2", "fizz", "4", "buzz", "fizz", "7", "8", "fizz", "buzz", "11", "fizz", "13", "14", "fizz buzz"]

StringBuffer的用法，append方法的参数可以使boolean, char, char[], CharSequence, double, float, int, long, String, StringBuffer

class Solution {
    /**
     * param n: As description.
     * return: A list of strings.
     */
    public ArrayList<String> fizzBuzz(int n) {
        ArrayList<String> res = new ArrayList<String>();
        for (int i=1; i<=n; i++) {
            StringBuffer buf = new StringBuffer();
            if (i%3==0 && i%5!=0) {
                buf.append("fizz");
            }
            if (i%3!=0 && i%5==0) {
                buf.append("buzz");
            }
            if (i%3==0 && i%5==0) {
                buf.append("fizz buzz");
            }
            if (i%3!=0 && i%5!=0) {
                buf.append(i);
            }
            res.add(buf.toString());
        }
        return res;
    }
}

Better way: http://www.cnblogs.com/EdwardLiu/p/6121453.html