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  • Leetcode: Perfect Squares

    Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n.

For example, given n = 12, return 3 because 12 = 4 + 4 + 4; given n = 13, return 2 because 13 = 4 + 9.
     1 public class Solution {
 2     public int numSquares(int n) {
 3         int[] dp = new int[n+1];
 4         Arrays.fill(dp, Integer.MAX_VALUE);
 5         dp[0] = 0;
 6         for (int i=1; i<=n; i++) {
 7             int sqrt = (int)Math.sqrt(i);
 8             for (int j=1; j<=sqrt; j++) {
 9                 dp[i] = Math.min(dp[i], dp[i-j*j]+1);
10             }
11         }
12         return dp[n];
13     }
14 }
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  • 原文地址：https://www.cnblogs.com/EdwardLiu/p/5077413.html
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