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  • Leetcode: Flatten Nested List Iterator

    Given a nested list of integers, implement an iterator to flatten it.
    
    Each element is either an integer, or a list -- whose elements may also be integers or other lists.
    
    Example 1:
    Given the list [[1,1],2,[1,1]],
    
    By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,1,2,1,1].
    
    Example 2:
    Given the list [1,[4,[6]]],
    
    By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,4,6].

    非常精巧地使用stack。push all the nestedList into the stack from back to front,so when we pop the stack, it returns the very first element

    执行hasNext()的时候,如果peek()是integer, return true;否则是一个List<NestedInteger>, 则flatten这个list,同样的,把list里的NestedInteger倒序push入栈

     1 /**
     2  * // This is the interface that allows for creating nested lists.
     3  * // You should not implement it, or speculate about its implementation
     4  * public interface NestedInteger {
     5  *
     6  *     // @return true if this NestedInteger holds a single integer, rather than a nested list.
     7  *     public boolean isInteger();
     8  *
     9  *     // @return the single integer that this NestedInteger holds, if it holds a single integer
    10  *     // Return null if this NestedInteger holds a nested list
    11  *     public Integer getInteger();
    12  *
    13  *     // @return the nested list that this NestedInteger holds, if it holds a nested list
    14  *     // Return null if this NestedInteger holds a single integer
    15  *     public List<NestedInteger> getList();
    16  * }
    17  */
    18 public class NestedIterator implements Iterator<Integer> {
    19     Stack<NestedInteger> st;
    20     
    21     public NestedIterator(List<NestedInteger> nestedList) {
    22         st = new Stack<NestedInteger>();
    23         for (int i=nestedList.size()-1; i>=0; i--) {
    24             st.push(nestedList.get(i));
    25         }
    26     }
    27 
    28     @Override
    29     public Integer next() {
    30         return st.pop().getInteger();
    31     }
    32 
    33     @Override
    34     public boolean hasNext() {
    35         while (!st.isEmpty()) {
    36             if (st.peek().isInteger()) return true;
    37             List<NestedInteger> cur = st.pop().getList();
    38             for (int i=cur.size()-1; i>=0; i--) {
    39                 st.push(cur.get(i));
    40             }
    41         }
    42         return false;
    43     }
    44 }
    45 
    46 /**
    47  * Your NestedIterator object will be instantiated and called as such:
    48  * NestedIterator i = new NestedIterator(nestedList);
    49  * while (i.hasNext()) v[f()] = i.next();
    50  */
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  • 原文地址:https://www.cnblogs.com/EdwardLiu/p/6096255.html
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