Implement a simple stock price display systemwhich will show High, Low and Last price for a given stock throughout one day.The data comes from a real-time feed and have the following messages: PriceUpdate(t, P) -> Price of Stock A at timet is P. Correction(t, NewP) -> Price of Stock A attime t is rectified to NewP Remove(t) -> Disregard the price feedreceived at time t. PriceUpdate(10100,850.50) -> high = 850.50, Low = 850.50, Last = 850.50 PriceUpdate(10200,852.25) -> high = 852.25, Low = 850.50, Last = 852.25 PriceUpdate(10300,848.00) -> high = 852.25, Low = 848.00, Last = 848.00 Correction(10200, 849.00) -> high = 850.50, Low = 848.00, Last 848.00 PriceUpdate(10400,855.00) -> high = 855.00, Low = 848.00, Last = 855.00 Correction(10300, 853.00) -> high = 855.00, Low = 850.50, Last = 855.00 PriceUpdate(10500,854.00) -> high = 855.00, Low = 848.00, Last = 854.00 Correction(10500,853.25) -> high = 855.00, Low = 848.00, Last = 853.25 Remove(10300) -> high = 855.00, Low = 849.00, Last = 853.25 简单说来PriceUpdate就是添加新的(timestamp, price), Correction是改之前的(timestamp, price), 求实现当前high(), low(), last()
简单说来PriceUpdate就是添加新的(timestamp, price), Correction是改之前的(timestamp, price), 求实现当前high(), low(), last()
LZ是用的Heap + HashMap, 特别问了时间复杂度(我猜到他想考heap的remove(obj)复杂度)
follow Up是: 有没有办法把复杂度降到O(logN)
LZ是用的Heap + HashMap, 特别问了时间复杂度(我猜到他想考heap的remove(obj)复杂度)
LZ是用treeMap代替了Heap,这样代价是每次找high,low也要logN search整个tree了
感觉需要2个数据结构:
1. TreeMap<Long, Double> time2priceMap.
2. TreeMap<Double, Integer> price2countMap
priceupdate: insert new record into time2priceMap, update price count in price2countmap
correction: update record in time2pricemap, update prev price count, update prev price count (if 0, remove record), update new price count or needs to insert a new price record into price2countmap
high and low: lastkey and firstkey from price2countmap
last: last entry's price from time2pricemap
补充内容 (2017-2-4 07:00):
这样好像都是O(log(n))
1. TreeMap<Long, Double> time2priceMap.
2. TreeMap<Double, Integer> price2countMap
priceupdate: insert new record into time2priceMap, update price count in price2countmap
correction: update record in time2pricemap, update prev price count, update prev price count (if 0, remove record), update new price count or needs to insert a new price record into price2countmap
high and low: lastkey and firstkey from price2countmap
last: last entry's price from time2pricemap
补充内容 (2017-2-4 07:00):
这样好像都是O(log(n))