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  • cf1440 Greedy Shopping

    传送门
    操作:

    • 区间([1, x])进行修改,把(a_i = max(a_i, y))
    • 区间查询,求最大的(r),满足(sum(x,r) leq y)

    维护一下区间最大值和区间最小值,考虑到如果说某个区间的最大值(leq y),那么就变成了区间覆盖了,把区间的值都变成(y)
    如果说区间最小值都大于(y),那么这个区间就不需要进行更新。
    对于操作2,就是线段树的定义吧,先访问左边,再访问右边,他肯定是从左边的一段区间进行查询,再查询右边的,所以直接在query那里用应用就行了。

    #include <iostream>
    #include <cstdio>
    #include <algorithm>
    #define ll long long
    using namespace std;
    const int N = 2e5 + 5;
    int a[N];
    struct SegTree{
        struct Node{
            int l, r; ll sum, mx, mi, lazy;
            #define l(p) tree[p].l
            #define r(p) tree[p].r
            #define sum(p) tree[p].sum
            #define lazy(p) tree[p].lazy
            #define mx(p) tree[p].mx
            #define mi(p) tree[p].mi
            #define lson (p << 1)
            #define rson (p << 1 | 1)
        } tree[N << 2];
        void pushup(int p){
            sum(p) = sum(lson) + sum(rson);
            mi(p) = min(mi(lson), mi(rson));
            mx(p) = max(mx(lson), mx(rson));
        }
        void addtag(int p, int d){
            sum(p) = 1ll * (r(p) - l(p) + 1) * d;
            lazy(p) = mx(p) = mi(p) = d;
        }
        void pushdown(int p){
            if(lazy(p) != -1) addtag(lson, lazy(p)), addtag(rson, lazy(p)), lazy(p) = -1;
        }
        void build(int p, int l, int r){
            l(p) = l, r(p) = r, sum(p) = mx(p) = mi(p) = 0; lazy(p) = -1;
            if(l == r) {
                mi(p) = mx(p) = sum(p) = a[l];
                return;
            }
            int mid = (l + r) >> 1;
            build(lson, l, mid), build(rson, mid + 1, r);
            pushup(p);
        }
        void change(int p, int l, int r, int y){ // [l, r]区间修改为y
            if(l <= l(p) && r(p) <= r) {
                if(mi(p) >= y) return; // 无需更新
                if(mx(p) < y) {addtag(p, y); return;} // 这段区间都更新为最大值
                if(l(p) == r(p)) return;
            }
            pushdown(p);
            int mid = (l(p) + r(p)) >> 1;
            if(l <= mid) change(lson, l, r, y);
            if(r > mid) change(rson, l, r, y);
            pushup(p);
        }
        ll query(int p, int l, int r,  int &x) {
            if(l <= l(p) && r(p) <= r) {
                if(mi(p) > x) return 0;
                if(x >= sum(p)) {x -= sum(p); return r(p) - l(p) + 1;}
                if(l(p) == r(p)) return 0;
            }
            pushdown(p);
            int mid = (l(p) + r(p)) >> 1; ll ans = 0;
            if(l <= mid) ans += query(lson, l, r, x);
            if(r > mid) ans += query(rson, l, r, x);
            return ans;
        }
    } seg;
    int n, m;
    void task1(){
        int x, y; scanf("%d%d", &x, &y);
        seg.change(1, 1, x, y);
    }
    void task2(){
        int x, y; scanf("%d%d", &x, &y);
        printf("%lld
    ", seg.query(1, x, n, y));
    }
    int main(){
        scanf("%d%d", &n, &m);
        for(int i = 1; i <= n; i++) scanf("%d", &a[i]);
        seg.build(1, 1, n);
        for(int i = 1; i <= m; i++) {
            int op; scanf("%d", &op);
            if(op == 1) task1();
            if(op == 2) task2();
        }
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/Emcikem/p/14030261.html
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