zoukankan      html  css  js  c++  java
  • Windows Message Queue--hdu1509

    Windows Message Queue

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 4395    Accepted Submission(s): 1745


     

    Problem Description

     

    Message queue is the basic fundamental of windows system. For each process, the system maintains a message queue. If something happens to this process, such as mouse click, text change, the system will add a message to the queue. Meanwhile, the process will do a loop for getting message from the queue according to the priority value if it is not empty. Note that the less priority value means the higher priority. In this problem, you are asked to simulate the message queue for putting messages to and getting message from the message queue.

     

     

     

    Input

     

    There's only one test case in the input. Each line is a command, "GET" or "PUT", which means getting message or putting message. If the command is "PUT", there're one string means the message name and two integer means the parameter and priority followed by. There will be at most 60000 command. Note that one message can appear twice or more and if two messages have the same priority, the one comes first will be processed first.(i.e., FIFO for the same priority.) Process to the end-of-file.

     

     

     

    Output

     

    For each "GET" command, output the command getting from the message queue with the name and parameter in one line. If there's no message in the queue, output "EMPTY QUEUE!". There's no output for "PUT" command.

     

     

     

    Sample Input

     

     

     

    GET
    PUT msg1 10 5
    PUT msg2 10 4
    GET
    GET
    GET

     

    Sample Output

     

    EMPTY QUEUE!
    msg2 10
    msg1 10
    EMPTY QUEUE!

     

     
    这个题的大意是:输入GET就输出输入的数据,如果没数据就输出EMPTY QUEUE!
    每个数据都有优先级,优先级越小越先输出!优先级相同时,谁先输入谁就先输出!
     
     
    分析:用优先级数列来做
     
     
     
     
     
     
     
     1 #include<stdio.h>
     2 #include<string.h>
     3 #include<algorithm>
     4 #include<queue>
     5 #define max 60010
     6 using namespace std;
     7 struct as
     8 {
     9     char a[80];
    10     int b,c,d;
    11     bool friend operator <(as x,as y)
    12     {
    13         if(x.c!=y.c)
    14             return x.c>y.c;//如果优先级不相等,从小到大排 
    15         else
    16             return x.d>y.d;//如果优先级相等,按输入先后顺序排 
    17      } 
    18 }aa[max];
    19 priority_queue<struct as>q;
    20 char str[80];
    21 int main()
    22 {
    23     int i=0,j,k,n;
    24     while(scanf("%s",str)!=EOF)
    25     {
    26         getchar();
    27         if(strcmp(str,"PUT")==0)
    28         {
    29             scanf("%s",aa[i].a);
    30             scanf("%d %d",&aa[i].b,&aa[i].c);//输入参数和优先级 
    31             aa[i].d=i;//记录输入的先后次序,以便aa[i].y相等时比较 
    32             q.push(aa[i]);
    33             i++;
    34         }
    35         else if(strcmp(str,"GET")==0)
    36         {
    37             if(q.empty())
    38             printf("EMPTY QUEUE!
    ");
    39             else
    40             {
    41                 struct as er=q.top();
    42                 q.pop();
    43                 printf("%s %d
    ",er.a,er.b);
    44             }
    45          } 
    46     }
    47     return 0;
    48 }

     

  • 相关阅读:
    10000个线程更新同一行数据
    CountDownLatchTest
    创建 oracle dblin
    extjs日期控件使用
    JAVA Date超强工具类,可直接取代util.Date使用
    JSP&Servlet学习手册
    JAVA 文本 TXT 操作工具类
    Leetcode 526.优美的排列
    Leetcode 525.连续数组
    Leetcode 523.连续的子数组和
  • 原文地址:https://www.cnblogs.com/Eric-keke/p/4683604.html
Copyright © 2011-2022 走看看