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  • 【转】在一个SQL Server表中一行的多个列找出最大值

    https://www.cnblogs.com/lyhabc/archive/2015/10/21/4899244.html

    有时候我们需要从多个相同的列里(这些列的数据类型相同)找出最大的那个值,并显示

    这里给出一个例子

    IF (OBJECT_ID('tempdb..##TestTable') IS NOT NULL)
        DROP TABLE ##TestTable
    
    CREATE TABLE ##TestTable
    (
        ID INT IDENTITY(1,1) PRIMARY KEY,
        Name NVARCHAR(40),
        UpdateByApp1Date DATETIME,
        UpdateByApp2Date DATETIME,
        UpdateByApp3Date DATETIME
    
    )
    
    INSERT INTO ##TestTable(Name, UpdateByApp1Date, UpdateByApp2Date, UpdateByApp3Date )
    VALUES('ABC', '2015-08-05','2015-08-04', '2015-08-06'),
          ('NewCopmany', '2014-07-05','2012-12-09', '2015-08-14'),
          ('MyCompany', '2015-03-05','2015-01-14', '2015-07-26')
          
    SELECT * FROM ##TestTable

    结果如下所示

     

     

    有三种方法可以实现

    方法一

    SELECT  ID ,
            Name ,
            ( SELECT    MAX(LastUpdateDate)
              FROM      ( VALUES ( UpdateByApp1Date), ( UpdateByApp2Date),
                        ( UpdateByApp3Date) ) AS UpdateDate ( LastUpdateDate )
              ) AS LastUpdateDate
    FROM    ##TestTable

    方法二

    SELECT  ID ,
            [Name] ,
            MAX(UpdateDate) AS LastUpdateDate
    FROM    ##TestTable UNPIVOT ( UpdateDate FOR DateVal IN ( UpdateByApp1Date,
                                                              UpdateByApp2Date,
                                                              UpdateByApp3Date ) ) AS u
    GROUP BY ID ,
            Name

    方法三

    SELECT  ID ,
            name ,
            ( SELECT    MAX(UpdateDate) AS LastUpdateDate
              FROM      ( SELECT    tt.UpdateByApp1Date AS UpdateDate
                          UNION
                          SELECT    tt.UpdateByApp2Date
                          UNION
                          SELECT    tt.UpdateByApp3Date
                        ) ud
            ) LastUpdateDate
    FROM    ##TestTable tt

    第一种方法使用values子句,将每行数据构造为只有一个字段的表,以后求最大值,非常巧妙

    第二种方法使用行转列经常用的UNPIVOT 关键字进行转换再显示

    第三种方法跟第一种方法差不多,但是使用union将三个UpdateByAppDate字段合并为只有一个字段的结果集然后求最大值

     

    第一种方法的执行计划

     

    第二种方法的执行计划

     

    第三种方法的执行计划

     

     

    总的来说,第一种方法的执行计划是最好的

     

    注意,这里不涉及分组

    IF (OBJECT_ID('tempdb..##TestTable') IS NOT NULL)
        DROP TABLE ##TestTable
    
    CREATE TABLE ##TestTable
        (
          ID INT IDENTITY(1, 1)
                 PRIMARY KEY ,
          Name NVARCHAR(40) ,
          UpdateByApp1Date DATETIME ,
          UpdateByApp2Date DATETIME ,
          UpdateByApp3Date DATETIME
        )
    
    INSERT  INTO ##TestTable
            ( Name, UpdateByApp1Date, UpdateByApp2Date, UpdateByApp3Date )
    VALUES  ( 'ABC', '2015-08-05', '2015-08-04', '2015-08-06' ),
            ( 'ABC', '2015-07-05', '2015-06-04', '2015-09-06' ),
            ( 'NewCopmany', '2014-07-05', '2012-12-09', '2015-08-14' ),
            ( 'MyCompany', '2015-03-05', '2015-01-14', '2015-07-26' )
          
    SELECT  *
    FROM    ##TestTable
    
    SELECT  ID ,
            Name ,
            ( SELECT    MAX(LastUpdateDate)
              FROM      ( VALUES ( UpdateByApp1Date), ( UpdateByApp2Date),
                        ( UpdateByApp3Date) ) AS UpdateDate ( LastUpdateDate )
              ) AS LastUpdateDate
    FROM    ##TestTable

    name列相同的话,是无法得出name分组之后的最大值,这里要注意一下

     

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  • 原文地址:https://www.cnblogs.com/FH-cnblogs/p/8044424.html
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