hello
((a+b)^2 = a^2 + 2ab + b^2)
(f_{i,j}=max exttt{{} f_{i-1,j}+a_i,f_{i-1,0} exttt{}})
(f_{i} = min exttt{{} f_j + S_i - S_j exttt{}})
( exttt{%})
( exttt{}})
(O(n))
(ax^2+bx+c=0)
$ x = {-b pm sqrt{b^2-4ac} over 2a}. (
) x = {-b +sqrt{b^2-4ac} over 2a}. (
) sqrt{a} (
) pm (
) {x^2 over a^2} + {y^2 over b^2} =1 (
) _sum $
#include<iostream>
#include<cmath>
#include<cstring>
#include<cstdio>
#include<algorithm>
#include<queue>
using namespace std;
typedef long long LL;
#define mem(a,b) memset(a,b,sizeof(a))
typedef pair<int,int> PII;
inline int read()
{
int x=0,f=1;char c=getchar();
while(!isdigit(c)){if(c=='-')f=-1;c=getchar();}
while(isdigit(c)){x=x*10+c-'0';c=getchar();}
return x*f;
}
int main()
{
return 0;
}
Dijkstra
我的博客!
Rolling Sky
题解#
测试数据##
总结###
酯化反应
脱水缩合
静电感应
双曲线###
http://www.cnblogs.com/FYH-SSGSS/p/7348163.html
戳这里
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正如我轻轻地来