zoukankan      html  css  js  c++  java
  • Django页面跳转但是不会显示出来???

    一脸懵逼,点击登录,如果错了会有提示,但是登录成功了后台会显示跳转到dashboard上,也能正常获取到cookie,但是就是页面不会变化,单独访问dashboard也是正常的。
    问题代码如下:

    # login   
    
    
    class Login(View):
        '''
        用户登录
        '''
        def get(self, request):
            return render(request, 'website/signin.html')
    
        def post(self, request):
            res = {'status': 'succ'}
            user_name = request.POST.get("name", None)
            password = request.POST.get("password", None)
            u = models.WebsiteUserinfo.objects.filter(username=user_name).first()
            if not u:
                res['status'] = '用户名错误'
            else:
                if password == u.password:
                    # re = render(request,'website/dashboard.html')
                    re = redirect('/oa/dashboard')
                    re.set_cookie('is_log', True)  # 设置cookie
                    re.set_cookie('username', user_name)
                    return re
                else:
                    res['status'] = '密码错误'
            return HttpResponse(json.dumps(res), content_type="application/json")
    
    
    #  dashboard
    
    class Dashboard(View):
        '''
        主页
        '''
        def get(self, request):
            print(request.COOKIES['username'])
            return render(request, '../templates/website/dashboard.html', {'auth': '1234'})
    
    
    
    #  路由配置
    
    from django.conf.urls import url,include
    from django.contrib import admin
    from website import views
    
    urlpatterns = [
        url(r'^admin/', admin.site.urls),
        url(r'^$',views.init),
        url(r'^oa/', include('website.urls')),
    ]
    
    
    from django.conf.urls import url
    from website import views
    urlpatterns = [
        url(r'^dashboard', views.Dashboard.as_view()),
        url(r'^realtime_table', views.RealTimeTable.as_view()),
        url(r'^everyday_table', views.EveryDayTable.as_view()),
        url(r'^login', views.Login.as_view()),
    ]

    后台输出:

    解决问题:

    注意力一直放在后台上了,之前是通过session保存用户状态的,现在需要改为cookie验证,如果要设置cookie返回类型必须为render,redirect,因此就将原来登录成功返回json改为了redirect,但是没有想到的是前端是通过Ajax发送消息的,无法识别返回类型,就导致了登录成功了却没有反应。总结来说是一个很、非常、超级低端的问题,只怪自己想当然的修改。

    还是返回json格式,让js去设置cookie

    function login() {
            $.ajax({
                type: "POST",//方法类型
                dataType: "json",//预期服务器返回的数据类型
                url: "/oa/login",//url
                data: $('#login_form').serialize(),
                success: function (data) {
                    if (data['status'] != "succ"){
                        alert(data['status']);
                    }
                    if (data['status'] == "succ"){
                        var name = document.getElementById('u1').value;
                        document.cookie="is_log=True;";
                        document.cookie="username="+name;
                        window.location.href='/oa/dashboard';
                    }
                }
            });
        }
  • 相关阅读:
    Centos7 ifconfig命令找不到
    request的各种方法
    linux开放端口
    easyui datagrid 部分参数
    设置tomcat内存
    tomcat做成系统服务
    Meta-analysis with complex research designs: dealing with dependence from multiple measures and multiple group comparisons
    多重校正
    DTI
    learning source archive
  • 原文地址:https://www.cnblogs.com/FanMLei/p/10501011.html
Copyright © 2011-2022 走看看