Every girl likes shopping,so does dandelion.Now she finds the shop is increasing the price every day because the Spring Festival is coming .She is fond of a shop which is called "memory". Now she wants to know the rank of this shop's price after the change of everyday.
InputOne line contians a number n ( n<=10000),stands for the number of shops.
Then n lines ,each line contains a string (the length is short than 31 and only contains lowercase letters and capital letters.)stands for the name of the shop.
Then a line contians a number m (1<=m<=50),stands for the days .
Then m parts , every parts contians n lines , each line contians a number s and a string p ,stands for this day ,the shop p 's price has increased s.
OutputContains m lines ,In the ith line print a number of the shop "memory" 's rank after the ith day. We define the rank as :If there are t shops' price is higher than the "memory" , than its rank is t+1.Sample Input
3 memory kfc wind 2 49 memory 49 kfc 48 wind 80 kfc 85 wind 83 memorySample Output
1 2
map的使用
#include <iostream> #include <map> #include <string> using namespace std; int main() { int t; while(cin>>t) { string s; for(int i=0;i<t;i++) { cin>>s; } int m; cin>>m; map<string,int>shop; int p; string na; while(m--) { for(int i=0;i<t;i++) { cin>>p>>na; shop[na]+=p; } int ans; ans=1; map<string,int>::iterator it; for(it=shop.begin();it!=shop.end();it++) { if(it->second>shop["memory"]) { ans++; } } cout<<ans<<endl; } } return 0; }