思路
方法:对称遍历
1 class Solution { 2 public: 3 vector<int> constructArr(vector<int>& a) { 4 if(a.empty()) 5 return vector<int>(); 6 7 vector<int> b(a.size()); 8 b[0] = 1; 9 10 for(int i = 1; i < b.size(); ++i) { 11 b[i] = b[i-1] * a[i-1]; 12 } 13 14 int tmp = 1; 15 for(int i = b.size()-2; i >= 0; --i) { 16 tmp *= a[i+1]; 17 b[i] *= tmp; 18 } 19 20 return b; 21 } 22 };