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  • Python 编程(小试水)

    一. Python 冒泡法排序
    def sequence(arrays=list()):

    def desc():
    for i in range(1, len(arrays)):
    for j in range(len(arrays) - i):
    if arrays[j] < arrays[j + 1]:
    arrays[j], arrays[j + 1] = arrays[j + 1], arrays[j]
    return arrays

    def asc():
    for i in range(1, len(arrays)):
    for j in range(len(arrays) - i):
    if arrays[j] > arrays[j + 1]:
    arrays[j], arrays[j + 1] = arrays[j + 1], arrays[j]
    return arrays

    print desc()
    print asc()

    if __name__ == "__main__":

    sequence([1, 2, -1, 10, 12, 9, 13, 14])

    二. 有1、2、3、4个数字,能组成多少个互不相同且无重复数字的三位数?都是多少?
    def combinations():

    num = [1, 2, 3, 4]
       # 列表解析
    res = [i * 100 + j * 10 + k for i in num for j in num for k in num if(j != i and k != j and k != i)]

    print (res)

    if __name__ == "__main__":

    combinations()


    三、输出100以内的质数(大于1的且因数只有它自身与1的自然数)
    def prime_num():

    count = 0

    for i in range(2, 100):

    for j in range(2, i):
    if i % j == 0:
    break
    else:
    print i,
    count += 1

    print
    print "total: " + str(count)


    if __name__ == "__main__":

    prime_num()
    四、打印九九乘法表
    
    
    def multiplication_tables():

    for i in range(1, 10):
    print

    for j in range(1, i + 1):
    print "%d*%d=%d" % (i, j, i * j),

    if __name__ == "__main__":

    multiplication_tables()
    五、斐波那契数列
    def recur_fibo(n):
       """递归函数
       输出斐波那契数列"""
       if n <= 1:
           return n
       else:
           return(recur_fibo(n-1) + recur_fibo(n-2))
     
    # 获取用户输入
    nterms = int(input("您要输出几项? "))
     
    # 检查输入的数字是否正确
    if nterms <= 0:
       print("输入正数")
    else:
       print("斐波那契数列:")
       for i in range(nterms):
           print(recur_fibo(i))


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  • 原文地址:https://www.cnblogs.com/FengZiQ/p/8025392.html
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