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  • Codeforces Beta Round #61 (Div. 2)

    Codeforces Beta Round #61 (Div. 2)

    http://codeforces.com/contest/66

    A

    输入用long double

     1 #include<bits/stdc++.h>
     2 using namespace std;
     3 #define lson l,mid,rt<<1
     4 #define rson mid+1,r,rt<<1|1
     5 #define sqr(x) ((x)*(x))
     6 #define pb push_back
     7 #define eb emplace_back
     8 #define maxn 1000006
     9 #define rep(k,i,j) for(int k=i;k<j;k++)
    10 typedef long long ll;
    11 typedef unsigned long long ull;
    12 
    13 int main(){
    14     #ifndef ONLINE_JUDGE
    15         freopen("input.txt","r",stdin);
    16     #endif
    17     std::ios::sync_with_stdio(false);
    18     long double n;
    19     cin>>n;
    20     if(n>=-128&&n<=127) cout<<"byte"<<endl;
    21     else if(n>=-32768&&n<=32767) cout<<"short"<<endl;
    22     else if(n>=-2147483648&&n<=2147483647) cout<<"int"<<endl;
    23     else if(n<9223372036854775808) cout<<"long"<<endl;
    24     else{
    25         cout<<"BigInteger"<<endl;
    26     }
    27 }
    View Code

    B

    暴力枚举每一个数即可

     1 #include<bits/stdc++.h>
     2 using namespace std;
     3 #define lson l,mid,rt<<1
     4 #define rson mid+1,r,rt<<1|1
     5 #define sqr(x) ((x)*(x))
     6 #define pb push_back
     7 #define eb emplace_back
     8 #define maxn 1000006
     9 #define rep(k,i,j) for(int k=i;k<j;k++)
    10 typedef long long ll;
    11 typedef unsigned long long ull;
    12 
    13 int a[1005];
    14 
    15 int main(){
    16     #ifndef ONLINE_JUDGE
    17    //     freopen("input.txt","r",stdin);
    18     #endif
    19     std::ios::sync_with_stdio(false);
    20     int n;
    21     cin>>n;
    22     for(int i=1;i<=n;i++){
    23         cin>>a[i];
    24     }
    25     int ans=1;
    26     for(int i=1;i<=n;i++){
    27         int j=i-1;
    28         int co=1;
    29         while(j>=1){
    30             if(a[j+1]>=a[j]){
    31                 j--;
    32                 co++;
    33             }
    34             else{
    35                 break;
    36             }
    37         }
    38         j=i+1;
    39         while(j<=n){
    40             if(a[j-1]>=a[j]){
    41                 j++;
    42                 co++;
    43             }
    44             else{
    45                 break;
    46             }
    47         }
    48         if(co>ans) ans=co;
    49     }
    50     cout<<ans<<endl;
    51 }
    View Code

    C

    模拟题

     1 #include<bits/stdc++.h>
     2 using namespace std;
     3 #define lson l,mid,rt<<1
     4 #define rson mid+1,r,rt<<1|1
     5 #define sqr(x) ((x)*(x))
     6 #define pb push_back
     7 #define eb emplace_back
     8 #define maxn 1000006
     9 #define rep(k,i,j) for(int k=i;k<j;k++)
    10 typedef long long ll;
    11 typedef unsigned long long ull;
    12 
    13 string s,t;
    14 int res1,res2;
    15 map<string,int> M,N;
    16 
    17 int main(){
    18     #ifndef ONLINE_JUDGE
    19         freopen("input.txt","r",stdin);
    20     #endif
    21     std::ios::sync_with_stdio(false);
    22     while(cin>>t)
    23     {
    24         s=t;
    25         int F=0;
    26         while(1)
    27         {
    28             int x=s.find_last_of('\');
    29             if (x==2) break;
    30             s=s.substr(0,x);
    31             int f=N[s];
    32             M[s]+=F;
    33             N[s]++;
    34             res1=max(res1,M[s]);
    35             res2=max(res2,N[s]);
    36             if (!f) F++;
    37         }
    38     }
    39     cout<<res1<<' '<<res2<<endl;
    40 }
    View Code

    D

    找出3个数,使他们两两的公约数互不为1,他们三个的公约数为1,剩下的数就输出他们的倍数即可

     1 #include<bits/stdc++.h>
     2 using namespace std;
     3 #define lson l,mid,rt<<1
     4 #define rson mid+1,r,rt<<1|1
     5 #define sqr(x) ((x)*(x))
     6 #define pb push_back
     7 #define eb emplace_back
     8 #define maxn 1000006
     9 #define rep(k,i,j) for(int k=i;k<j;k++)
    10 typedef long long ll;
    11 typedef unsigned long long ull;
    12 
    13 int a[3]={6,10,15};
    14 
    15 int main(){
    16     #ifndef ONLINE_JUDGE
    17      //   freopen("input.txt","r",stdin);
    18     #endif
    19     std::ios::sync_with_stdio(false);
    20     int n;
    21     cin>>n;
    22     if(n==2){
    23         cout<<-1<<endl;
    24     }
    25     else{
    26         for(int i=0;i<n;i++){
    27             if(i<3){
    28                 cout<<a[i]<<endl;
    29             }
    30             else{
    31                 cout<<6*i<<endl;
    32             }
    33         }
    34     }
    35 }
    View Code

    E

    找出a[i]-b[i]前缀和的最小值,然后依次减去,如果发现minn大于等于0的情况,说明走的通,逆向同理

     1 #include<bits/stdc++.h>
     2 using namespace std;
     3 #define lson l,mid,rt<<1
     4 #define rson mid+1,r,rt<<1|1
     5 #define sqr(x) ((x)*(x))
     6 #define pb push_back
     7 #define eb emplace_back
     8 #define maxn 1000006
     9 #define rep(k,i,j) for(int k=i;k<j;k++)
    10 typedef long long ll;
    11 typedef unsigned long long ull;
    12 
    13 int n;
    14 int a[100005];
    15 int b[100005];
    16 set<int>se;
    17 set<int>::iterator it;
    18 
    19 void func(int x){
    20     int minn=a[0]-b[0],pre=minn;
    21     for(int i=1;i<n;i++){
    22         pre+=a[i]-b[i];
    23         minn=min(minn,pre);
    24     }
    25     for(int i=0;i<n;i++){
    26         if(minn>=0){
    27             if(x){
    28                 se.insert(i+1);
    29             }
    30             else{
    31                 se.insert(n-i);
    32             }
    33         }
    34         minn-=a[i]-b[i];
    35     }
    36 }
    37 
    38 int main(){
    39     #ifndef ONLINE_JUDGE
    40      //   freopen("input.txt","r",stdin);
    41     #endif
    42     std::ios::sync_with_stdio(false);
    43     cin>>n;
    44     rep(i,0,n) cin>>a[i];
    45     rep(i,0,n) cin>>b[i];
    46     func(1);
    47     reverse(a,a+n);
    48     reverse(b,b+n-1);
    49     func(0);
    50     cout<<se.size()<<endl;
    51     for(it=se.begin();it!=se.end();it++){
    52         cout<<*it<<" ";
    53     }
    54 }
    View Code
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  • 原文地址:https://www.cnblogs.com/Fighting-sh/p/10456922.html
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