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  • Problem 1004-2017 ACM/ICPC Asia Regional Shenyang Online

    • 题目来源:array array array
    • Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
      Total Submission(s): 0 Accepted Submission(s): 0
    • 题目描述和输出:
      One day, Kaitou Kiddo had stolen a priceless diamond ring. But detective Conan blocked Kiddo’s path to escape from the museum. But Kiddo didn’t want to give it back. So, Kiddo asked Conan a question. If Conan could give a right answer, Kiddo would return the ring to the museum.
      Kiddo: “I have an array A and a number k, if you can choose exactly k elements from A and erase them, then the remaining array is in non-increasing order or non-decreasing order, we say A is a magic array. Now I want you to tell me whether A is a magic array. ” Conan: “emmmmm…” Now, Conan seems to be in trouble, can you help him?
    • Input
      The first line contains an integer T indicating the total number of test cases. Each test case starts with two integers n and k in one line, then one line with n integers: A1,A2…An.
      1≤T≤20
      1≤n≤10^5
      0≤k≤n
      1≤Ai≤10^5
    • Output
      For each test case, please output “A is a magic array.” if it is a magic array. Otherwise, output “A is not a magic array.” (without quotes).
    • Sample Input
      3
      4 1
      1 4 3 7
      5 2
      4 1 3 1 2
      6 1
      1 4 3 5 4 6
    • Sample Output
      A is a magic array.
      A is a magic array.
      A is not a magic array.
    • 题目分析:
      有T个测试样例,对于每个测试样例,给定两个整数,分别是数组元素个数n和需要删除的元素个数k,如果这个数组在删除了k个元素之后,是递增或者递减的,就称这个数组是magic array,否则不是。
    • 做法:这道题是个经典的DP,换句话说就是模板题。
    • 完整代码:
    #include<iostream>
    #include<algorithm>
    #include<cstdio>
    using namespace std;
    #define MAX 100005
    #define INF 100000000
    int dp[MAX];
    int a[MAX];
    int k, T, n, flag;
    int main()
    {
        int temp;
        cin >> T;
        while (T-- > 0)
        {
            cin >> n >> k;
            memset(a, 0, sizeof(int)*MAX);
            for (int i = 0; i < n; i++)
                cin >> a[i];
            fill(dp, dp + n, INF);
            for (int i = 0; i < n; i++)
            {
                *upper_bound(dp, dp + n, a[i]) = a[i];
            }
            temp = 0;
            while (dp[temp]<INF)
            {
                temp++;
            }
            if (temp >= n - k)
                printf("A is a magic array.
    ");
            else
                printf("A is not a magic array.
    ");
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/FlyerBird/p/9052564.html
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