把原图改造一下(>=mid)那么权值为1,反之为0
然后跑最长路,如果最长路不小于0,那么就可行,反之不行
#include<iostream>
#include<cstdio>
#include<algorithm>
#include<cstring>
#include<queue>
#define int long long
using namespace std;
int n,m;
long long Aimee[1000001];
int x,y;
queue<int> q;
struct b{
int to;
int ne;
} ed[1000001];
int Ai;
int head[1000001];
int vis[1000001];
int dp[1000001];
int tem[1000001];
void add(int f,int to){
Ai++;
ed[Ai].to=to;
ed[Ai].ne=head[f];
head[f]=Ai;
return ;
}
long long l,r;
int dfs(int no,int k){
if(vis[no])
return dp[no];
vis[no]=1;
for(int i=head[no];i;i=ed[i].ne){
dp[no]=max(dp[no],dfs(ed[i].to,k)+tem[ed[i].to]);
}
return dp[no];
}
bool check(int now){
for(int i=0;i<=n;++i){
tem[i]=(Aimee[i]>=now? 1 :-1);
vis[i]=0;
dp[i]=-999999999;
}
dp[n]=0;
vis[n]=1;
dfs(1,now);
dp[1]+=tem[1];
return dp[1]>=0;
}
signed main(){
scanf("%d%d",&n,&m);
for(int i=1;i<=n;++i){
scanf("%lld",&Aimee[i]);
}
for(int i=1;i<=m;++i){
scanf("%d%d",&x,&y);
add(x,y);
}
int ans;
ans=r=9999999990;
while(l<=r){
long long mid=l+(r-l)/2;
if(check(mid)){
l=mid+1;
ans=mid;
}else{
r=mid-1;
}
}
cout<<(ans==(long long)9999999990?-1 :ans);
return 0;
}