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  • HDU 1711:Number Sequence(KMP模板,求位置)

    Number Sequence

    Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
    Total Submission(s): 40388    Accepted Submission(s): 16659

    Problem Description

    Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make a[K] = b[1], a[K + 1] = b[2], ...... , a[K + M - 1] = b[M]. If there are more than one K exist, output the smallest one.

    Input

    The first line of input is a number T which indicate the number of cases. Each case contains three lines. The first line is two numbers N and M (1 <= M <= 10000, 1 <= N <= 1000000). The second line contains N integers which indicate a[1], a[2], ...... , a[N]. The third line contains M integers which indicate b[1], b[2], ...... , b[M]. All integers are in the range of [-1000000, 1000000].

    Output

    For each test case, you should output one line which only contain K described above. If no such K exists, output -1 instead.

    Sample Input

    2
    13 5
    1 2 1 2 3 1 2 3 1 3 2 1 2
    1 2 3 1 3
    13 5
    1 2 1 2 3 1 2 3 1 3 2 1 2
    1 2 3 2 1

    Sample Output

    6

    -1

    题意

    给出两个数组,问第二个数组是不是第一个数组的子序列,如果是,输出第二个数组的第一个元素在第一个数组中的位置,否则输出-1

    AC代码

    #include <bits/stdc++.h>
    #define ll long long
    #define ms(a) memset(a,0,sizeof(a))
    using namespace std;
    const int maxn=1e6+10;
    int a[maxn],b[maxn];
    int Next[maxn];
    int  n,m;
    // Next数组下标从1开始
    void getNext()
    {
    	int j,k;
    	j=0;k=-1;Next[0]=-1;
    	while(j<m)
    	{
    		if(k==-1||b[j]==b[k])
    			Next[++j]=++k;
    		else
    			k=Next[k];
    	}
    }
    /*
    返回第二个数组在第一个数组中首次出现的位置
    返回的位置是从0开始的。
    */
    int KMP_Index()
    {
    	int i=0,j=0;
    	getNext();
    	while(i<n&&j<m)
    	{
    		if(j==-1||a[i]==b[j])
    		{
    			i++;j++;
    		}
    		else
    			j=Next[j];
    	}
    	if(j==m)
    		return i-m;
    	else
    		return -1;
    }
    int main(int argc, char const *argv[])
    {
    	int t;
    	scanf("%d",&t);
    	while(t--)
    	{
    		scanf("%d%d",&n,&m);
    		ms(a);
    		ms(b);
    		ms(Next);
    		for(int i=0;i<n;i++)
    			scanf("%d",&a[i]);
    		for(int i=0;i<m;i++)
    			scanf("%d",&b[i]);
    		if(KMP_Index()!=-1)
    			printf("%d
    ",KMP_Index()+1);
    		else
    			printf("%d
    ",KMP_Index());
    	}
    	return 0;
    }
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  • 原文地址:https://www.cnblogs.com/Friends-A/p/10324386.html
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