HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",
- "Q" prints the source code of the program itself,
- "9" prints the lyrics of "99 Bottles of Beer" song,
- "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-sensitive and must be uppercase. The characters of the program which are not instructions are ignored.
You are given a program written in HQ9+. You have to figure out whether executing this program will produce any output.
The input will consist of a single line p which will give a program in HQ9+. String p will contain between 1 and 100 characters, inclusive. ASCII-code of each character of p will be between 33 (exclamation mark) and 126 (tilde), inclusive.
Output "YES", if executing the program will produce any output, and "NO" otherwise.
Hi!
YES
Codeforces
NO
In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions.
题意:输入字符串,判断里面是否有“H”“Q”“9”“+”这四个字符(区分大小写),输入“H”“Q”“9”均有输出,但是输入“+”,只进行累加操作,没有输出。如果输入的字符串有输出,则输出“YES”(“+”是NO!!!!)
#include <stdio.h>
#include <string.h>
#include <iostream>
#include <algorithm>
#include <math.h>
#include <limits.h>
#include <map>
#include <stack>
#include <queue>
#include <vector>
#define ll long long
#define ms(a) memset(a,0,sizeof(a))
#define pi acos(-1.0)
#define INF 0x3f3f3f3f
const double E=exp(1);
const int maxn=1e6+10;
using namespace std;
char ch[maxn];
int main(int argc, char const *argv[])
{
ios::sync_with_stdio(false);
cin>>ch;
int l=strlen(ch);
int flag=0;
for(int i=0;i<l;i++)
{
if(ch[i]=='H'||ch[i]=='Q'||ch[i]=='9')
flag++;
}
if(flag)
cout<<"YES"<<endl;
else
cout<<"NO"<<endl;
return 0;
}