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  • Groovy In Action 笔记 (5) -- List 相关

    list在Groovy中很重要,记录一下list的一些见操作:

    def list = []
    list << 2
    // list >> 2 // invalid
    assert list.size() == 1
    assert list == [2]
    
    //传统添加
    list.add(3)
    assert list.size() == 2 //groovy中统一的size 方法
    assert list == [2,3]
    
    list << "a"
    assert list.size() == 3
    assert list == [2,3,"a"] //groovy中不限制list中的数据类型,因为背后都是Object
    
    def other_list = [3]
    assert list - other_list == [2,"a"] // list可以直接相减
    
    def other_list_a = [3,"b"]
    assert list - other_list_a == [2,"a"] // list可以直接相减
    
    assert list * 2 == [2,3,"a",2,3,"a"] // list可以乘以一个数,达到复制效果
    
    assert list.intersect(other_list) == [3] // 取交集
    assert list.reverse() == ["a",3,2]
    assert !list.disjoint(other_list_a) // 判断有无交集
    
    list.each {item -> println(item)}
    assert list.collect({it*2}) == [4,6,"aa"] // map
    
    def list_items = [1,2,3]
    assert list_items.inject {x,y -> x * y} == 6 // reduce or fold
    assert list_items.findAll {it % 2 == 0} == [2] //取值为偶数元素
    assert list_items.join(",") == "1,2,3" // join 有时候很有用
    
    def complex_list = [1,2,[3,4]]
    assert complex_list.flatten() == [1,2,3,4]
    
    
    //indexing
    def long_list = [1,2,3,4,5,6,7,8]
    assert long_list[1..3] == [2,3,4]
    assert long_list[-1] == 8
    assert long_list[-1..-3] == [8,7,6]
    assert long_list[-1..0] == long_list.reverse() // 反转
    assert long_list[-1..-8] == long_list.reverse() // 反转
    assert long_list[1,2,4] == [2,3,5]
    assert long_list[0..<2] == [1,2]

    下面尝试一个简单的快排算法:

    /**
     * @author :ZackZhou
     * @date :Created in 2020/9/1 5:42 PM
     * @description :quick sort
     * @modified By:
     * @version:
     */
    
    
    def quickSort(List input_list)
    {
        if(input_list.size() < 2)
            return input_list
    
        int middle = input_list.size().intdiv(2)
    
        def middle_element = input_list.get(middle)
    
        def middle_list = input_list.findAll{item -> item == middle_element}
        def left_list = input_list.findAll{item -> item < middle_element}
        def right_list = input_list.findAll{item -> item > middle_element}
    
        return (quickSort(left_list) + middle_list + quickSort(right_list))
    }
    
    def raw_list = [3,24,5,6,6,7,82,6,7,2]
    
    quickSort(raw_list).each {println(it)}
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  • 原文地址:https://www.cnblogs.com/FsharpZack/p/13782577.html
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