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  • HDU 2602 Bone Collector

    Bone Collector

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
    Total Submission(s): 22357    Accepted Submission(s): 9071


    Problem Description
    Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
    The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?
     
    Input
    The first line contain a integer T , the number of cases.
    Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.
     
    Output
    One integer per line representing the maximum of the total value (this number will be less than 231).
     
    Sample Input
    1 5 10 1 2 3 4 5 5 4 3 2 1
     
    Sample Output
    14
     
    Author
    Teddy
     
    Source
     
    Recommend
    lcy
     
    思路:
     
    代码:

    #include <iostream>
    #include <cstring>
    #include <cstdio>
    #include <algorithm>
    using namespace std;
    int t,n,m;
    int map[1010][1010];
    int dp[1010];
    int max(int x,int y)
    {
    return x > y ? x : y;
    }
    int main()
    {
    scanf("%d",&t);
    while(t --)
    {
    scanf("%d%d",&n,&m);
    for(int i = 1;i <= n;i ++)
    scanf("%d",&map[i][0]);
    for(int i = 1;i <= n;i ++)
    scanf("%d",&map[i][1]);
    memset(dp,0,sizeof(dp));
    for(int i = 1;i <= n;i ++)
    for(int j = m;j >= map[i][1];j --)
    dp[j] = max(dp[j],dp[j - map[i][1]] + map[i][0]);
    printf("%d ",dp[m]);
    }
    }

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  • 原文地址:https://www.cnblogs.com/GODLIKEING/p/3327094.html
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