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  • bzoj 1798 [Ahoi2009]Seq 维护序列seq

    原题链接:http://www.lydsy.com/JudgeOnline/problem.php?id=1798 

    线段树区间更新:

     1. 区间同同时加上一个数
     2. 区间同时乘以一个数

     1 #include<algorithm>
     2 #include<iostream>
     3 #include<cstdlib>
     4 #include<cstdio>
     5 #define lc root<<1
     6 #define rc root<<1|1
     7 typedef unsigned long long ull;
     8 const int Max_N = 100010;
     9 int Mod;
    10 struct Node {
    11     ull sum, add, mul;
    12 };
    13 struct SegTree {
    14     Node seg[Max_N << 2];
    15     inline void push_up(int root) {
    16         seg[root].sum = (seg[lc].sum + seg[rc].sum) % Mod;
    17     }
    18     inline void built(int root, int l, int r) {
    19         seg[root].add = 0, seg[root].mul = 1;
    20         if (l == r) {
    21             scanf("%lld", &seg[root].sum);
    22             seg[root].sum %= Mod;
    23             return;
    24         }
    25         int mid = (l + r) >> 1;
    26         built(lc, l, mid);
    27         built(rc, mid + 1, r);
    28         push_up(root);
    29     }
    30     inline void push_down(int root, int len) {
    31         if (seg[root].add != 0 || seg[root].mul != 1) {
    32             ull &_add = seg[root].add, &_mul = seg[root].mul;
    33             seg[lc].sum = (seg[lc].sum * _mul + (len - (len >> 1)) * _add) % Mod;
    34             seg[lc].mul = (seg[lc].mul * _mul) % Mod;
    35             seg[lc].add = (seg[lc].add * _mul + _add) % Mod;
    36             seg[rc].sum = (seg[rc].sum * _mul + (len >> 1) * _add) % Mod;
    37             seg[rc].mul = (seg[rc].mul * _mul) % Mod;
    38             seg[rc].add = (seg[rc].add * _mul + _add) % Mod;
    39             _add = 0, _mul = 1;
    40         }
    41     }
    42     inline void update(int root, int l, int r, int x, int y, ull val, ull mul) {
    43         if (x > r || y < l) return;
    44         if (x <= l && y >= r) {
    45             seg[root].add = (seg[root].add * mul + val) % Mod;
    46             seg[root].mul = (seg[root].mul * mul) % Mod;
    47             seg[root].sum = (seg[root].sum * mul + val * (r - l + 1)) % Mod;
    48             return;
    49         }
    50         push_down(root, r - l + 1);
    51         int mid = (l + r) >> 1;
    52         update(lc, l, mid, x, y, val, mul);
    53         update(rc, mid + 1, r, x, y, val, mul);
    54         push_up(root);
    55     }
    56     inline ull query(int root, int l, int r, int x, int y) {
    57         if (x > r || y < l) return 0;
    58         if (x <= l && y >= r) {
    59             return seg[root].sum;
    60         }
    61         push_down(root, r - l + 1);
    62         ull ret = 0;
    63         int mid = (l + r) >> 1;
    64         ret += query(lc, l, mid, x, y);
    65         ret += query(rc, mid + 1, r, x, y);
    66         return ret %= Mod;
    67     }
    68 }seg;
    69 int main() {
    70 #ifdef LOCAL
    71     freopen("in.txt", "r", stdin);
    72     freopen("out.txt", "w+", stdout);
    73 #endif
    74     int n, m, a, b, c, d;
    75     while (~scanf("%d %d", &n, &Mod)) {
    76         seg.built(1, 1, n);
    77         scanf("%d", &m);
    78         while (m--) {
    79             scanf("%d", &a);
    80             if (1 == a) {
    81                 scanf("%d %d %d", &b, &c, &d);
    82                 seg.update(1, 1, n, b, c, 0, d);
    83             } else if (2 == a) {
    84                 scanf("%d %d %d", &b, &c, &d);
    85                 seg.update(1, 1, n, b, c, d, 1);
    86             } else {
    87                 scanf("%d %d", &b, &c);
    88                 printf("%lld
    ", seg.query(1, 1, n, b, c));
    89             }
    90         }
    91     }
    92     return 0;
    93 }
    View Code
     
    By: GadyPu 博客地址:http://www.cnblogs.com/GadyPu/ 转载请说明
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  • 原文地址:https://www.cnblogs.com/GadyPu/p/4528938.html
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