题目连接
http://acm.hdu.edu.cn/showproblem.php?pid=3282
Running Median
Description
For this problem, you will write a program that reads in a sequence of 32-bit signed integers. After each odd-indexed value is read, output the median (middle value) of the elements received so far.
Input
The first line of input contains a single integer $P, (1 leq P leq 1000)$, which is the number of data sets that follow. The first line of each data set contains the data set number, followed by a space, followed by an odd decimal integer $M, (1 leq M leq 9999)$, giving the total number of signed integers to be processed.
The remaining line(s) in the dataset consists of the values, 10 per line, separated by a single space.
The last line in the dataset may contain less than 10 values.
Output
For each data set the first line of output contains the data set number, a single space and the number of medians output (which should be one-half the number of input values plus one). The output medians will be on the following lines, 10 per line separated by a single space. The last line may have less than 10 elements, but at least 1 element. There should be no blank lines in the output.
SampleInput
3
1 9
1 2 3 4 5 6 7 8 9
2 9
9 8 7 6 5 4 3 2 1
3 23
23 41 13 22 -3 24 -31 -11 -8 -7
3 5 103 211 -311 -45 -67 -73 -81 -99
-33 24 56
SampleOutput
1 5
1 2 3 4 5
2 5
9 8 7 6 5
3 12
23 23 22 22 13 3 5 5 3 -3
-7 -3
动态的求中位数，套个平衡树即可。。
1 #include<algorithm> 2 #include<iostream> 3 #include<cstdlib> 4 #include<cstring> 5 #include<cstdio> 6 #include<vector> 7 #include<map> 8 #include<set> 9 using std::cin; 10 using std::cout; 11 using std::endl; 12 using std::find; 13 using std::sort; 14 using std::set; 15 using std::map; 16 using std::pair; 17 using std::vector; 18 #define sz(c) (int)(c).size() 19 #define all(c) (c).begin(), (c).end() 20 #define iter(c) decltype((c).begin()) 21 #define cls(arr,val) memset(arr,val,sizeof(arr)) 22 #define cpresent(c, e) (find(all(c), (e)) != (c).end()) 23 #define rep(i, n) for (int i = 0; i < (int)(n); i++) 24 #define fork(i, k, n) for (int i = (int)k; i <= (int)n; i++) 25 #define tr(c, i) for (iter(c) i = (c).begin(); i != (c).end(); ++i) 26 #define pb(e) push_back(e) 27 #define mp(a, b) make_pair(a, b) 28 const int Max_N = 10010; 29 typedef unsigned long long ull; 30 struct Node { 31 int v, s; 32 Node *ch[2]; 33 inline void setc(int _v, int _s, Node *p) { 34 v = _v, s = _s; 35 ch[0] = ch[1] = p; 36 } 37 inline void push_up() { 38 s = ch[0]->s + ch[1]->s + 1; 39 } 40 }; 41 struct SBT { 42 Node stack[Max_N]; 43 Node *root, *null, *tail; 44 inline void init() { 45 tail = &stack[0]; 46 null = tail++; 47 null->setc(0, 0, NULL); 48 root = null; 49 } 50 inline Node *newNode(int v) { 51 Node *p = tail++; 52 p->setc(v, 1, null); 53 return p; 54 } 55 inline void rotate(Node *&x, bool d) { 56 Node *k = x->ch[!d]; x->ch[!d] = k->ch[d]; k->ch[d] = x; 57 k->s = x->s; 58 x->push_up(); 59 x = k; 60 } 61 inline void Maintain(Node *&x, bool d) { 62 if (!x->ch[d]->s) return; 63 if (x->ch[d]->ch[d]->s > x->ch[!d]->s) rotate(x, !d); 64 else if (x->ch[d]->ch[!d]->s > x->ch[!d]->s) rotate(x->ch[d], d), rotate(x, !d); 65 else return; 66 Maintain(x, 0), Maintain(x, 1); 67 } 68 inline void insert(Node *&x, int v) { 69 if (!x->s) { x = newNode(v); return; } 70 bool d = v > x->v; x->s++; 71 insert(x->ch[d], v); 72 x->push_up(); 73 Maintain(x, d); 74 } 75 inline int kth(int k) { 76 int t; 77 Node *x = root; 78 for (; x->s;) { 79 t = x->ch[0]->s; 80 if (k == t + 1) break; 81 else if (k <= t) x = x->ch[0]; 82 else k -= t + 1, x = x->ch[1]; 83 } 84 return x->v; 85 } 86 inline void go() { 87 vector<int> res; 88 int v, q, n, k = 1; 89 scanf("%d %d", &q, &n); 90 printf("%d %d ", q, (n + 1) >> 1); 91 fork(i, 1, n) { 92 scanf("%d", &v); 93 insert(root, v); 94 if (i & 1) res.push_back(kth((root->s >> 1) + 1)); 95 } 96 n = sz(res); 97 rep(i, n) { 98 if ((i + 1) % 10) { 99 if (i == n - 1) printf("%d ", res[i]); 100 else printf("%d ", res[i]); 101 } 102 else printf("%d ", res[i]); 103 } 104 } 105 }sbt; 106 int main() { 107 #ifdef LOCAL 108 freopen("in.txt", "r", stdin); 109 freopen("out.txt", "w+", stdout); 110 #endif 111 int t; 112 scanf("%d", &t); 113 while (t--){ 114 sbt.init(); 115 sbt.go(); 116 } 117 return 0; 118 }