Max Sum 贪心

                                                                                                                    Max Sum

Description

Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max sum of a sub-sequence. For example, given (6,-1,5,4,-7), the max sum in this sequence is 6 + (-1) + 5 + 4 = 14. 

 

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line starts with a number N(1<=N<=100000), then N integers followed(all the integers are between -1000 and 1000). 

 

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line contains three integers, the Max Sum in the sequence, the start position of the sub-sequence, the end position of the sub-sequence. If there are more than one result, output the first one. Output a blank line between two cases. 

 

Sample Input

2 5 6 -1 5 4 -7 7 0 6 -1 1 -6 7 -5

 

Sample Output

Case 1: 14 1 4 Case 2: 7 1 6

 

#include<iostream>
using namespace std;
int a[100000];
void maxSubSum(int a[], int n){
    int maxSum=-1001, thisSum=-1001, start=0, end=0, p=0;
    for(int i=0; i<n; i++){
        if(thisSum + a[i] <a[i]){
            thisSum = a[i];
            p = i;
        }
        else  thisSum += a[i];
        if(thisSum > maxSum){
            maxSum = thisSum;
            start = p;
            end = i;
        }
    }
    cout<<maxSum<<" "<<start+1<<" "<<end+1<<endl;
}
int main(){
    int t, i;
    cin>>t;
    for(i=1; i<=t; i++){
        int n;
        cin>>n;
        for(int j=0; j<n; j++)  cin>>a[j];
        if(i!=1)  cout<<endl;
        cout<<"Case "<<i<<":"<<endl;
        maxSubSum(a, n);
    }
    return 0;
}