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  • Luogu1641 SCOI2010生成字符串(组合数学)

      NOI2018冒泡排序的一个子问题。

    #include<iostream> 
    #include<cstdio>
    #include<cmath>
    #include<cstdlib>
    #include<cstring>
    #include<algorithm>
    using namespace std;
    #define ll long long
    #define P 20100403
    #define N 2000010
    char getc(){char c=getchar();while ((c<'A'||c>'Z')&&(c<'a'||c>'z')&&(c<'0'||c>'9')) c=getchar();return c;}
    int gcd(int n,int m){return m==0?n:gcd(m,n%m);}
    int read()
    {
        int x=0,f=1;char c=getchar();
        while (c<'0'||c>'9') {if (c=='-') f=-1;c=getchar();}
        while (c>='0'&&c<='9') x=(x<<1)+(x<<3)+(c^48),c=getchar();
        return x*f;
    }
    int n,m,fac[N],inv[N];
    int C(int n,int m){return 1ll*fac[n]*inv[m]%P*inv[n-m]%P;}
    int main()
    {
    #ifndef ONLINE_JUDGE
        freopen("1641.in","r",stdin);
        freopen("1641.out","w",stdout);
        const char LL[]="%I64d
    ";
    #else
        const char LL[]="%lld
    ";
    #endif
        n=read(),m=read();
        fac[0]=1;for (int i=1;i<=n+m;i++) fac[i]=1ll*fac[i-1]*i%P;
        inv[0]=inv[1]=1;for (int i=2;i<=n+m;i++) inv[i]=P-1ll*(P/i)*inv[P%i]%P;
        for (int i=2;i<=n+m;i++) inv[i]=1ll*inv[i-1]*inv[i]%P;
        cout<<(C(n+m,m)-C(n+m,m-1)+P)%P;
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/Gloid/p/10187470.html
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