对反串建SAM弄出后缀树，每个b串通过倍增定位其在后缀树上对应的节点，根据其长度将节点拆开。然后每个a串也找到对应的节点，由该节点向表示a串的节点连边，再把所给的边连上跑拓扑排序即可。
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define N 800010
char getc(){char c=getchar();while ((c<'A'||c>'Z')&&(c<'a'||c>'z')&&(c<'0'||c>'9')) c=getchar();return c;}
int gcd(int n,int m){return m==0?n:gcd(m,n%m);}
int read()
{
int x=0,f=1;char c=getchar();
while (c<'0'||c>'9') {if (c=='-') f=-1;c=getchar();}
while (c>='0'&&c<='9') x=(x<<1)+(x<<3)+(c^48),c=getchar();
return x*f;
}
int T,n,na,nb,m,son[N][26],fail[N],len[N],id[N],f[N][21],pos[N],cnt,last;
char s[N];
struct data{int l,r;
}a[N],b[N];
int p[N],degree[N],q[N],val[N],t;
ll F[N];
struct data2{int to,nxt;
}edge[N<<1];
vector<int> node[N];
void addedge(int x,int y){t++;degree[y]++;edge[t].to=y,edge[t].nxt=p[x],p[x]=t;}
int newnode(){cnt++;memset(son[cnt],0,sizeof(son[cnt]));fail[cnt]=len[cnt]=0;node[cnt].clear();return cnt;}
void ins(int c)
{
int x=newnode(),p=last;last=x;len[x]=len[p]+1;id[len[x]]=x;
while (!son[p][c]&&p) son[p][c]=x,p=fail[p];
if (!p) fail[x]=1;
else
{
int q=son[p][c];
if (len[p]+1==len[q]) fail[x]=q;
else
{
int y=newnode();
len[y]=len[p]+1;
memcpy(son[y],son[q],sizeof(son[q]));
fail[y]=fail[q],fail[q]=fail[x]=y;
while (son[p][c]==q) son[p][c]=y,p=fail[p];
}
}
}
int find(int x,int y)
{
for (int j=20;~j;j--) if (len[f[x][j]]>=y) x=f[x][j];
return x;
}
int find2(int x,int y)
{
if (len[x]<=y) return x;
for (int j=20;~j;j--) if (len[f[x][j]]>y) x=f[x][j];
return fail[x];
}
bool cmp(int x,int y){return b[x].r<b[y].r;}
ll topsort()
{
int head=0,tail=0;
for (int i=1;i<=cnt;i++)
{
F[i]=val[i];
if (!degree[i]) q[++tail]=i;
}
while (head<tail)
{
int x=q[++head];
for (int i=p[x];i;i=edge[i].nxt)
{
degree[edge[i].to]--;
F[edge[i].to]=max(F[edge[i].to],F[x]+val[edge[i].to]);
if (!degree[edge[i].to]) q[++tail]=edge[i].to;
}
}
if (tail<cnt) return -1;
ll ans=0;
for (int i=1;i<=cnt;i++) ans=max(ans,F[i]);
return ans;
}
int main()
{
#ifndef ONLINE_JUDGE
freopen("a.in","r",stdin);
freopen("a.out","w",stdout);
const char LL[]="%I64d
";
#else
const char LL[]="%lld
";
#endif
T=read();
while (T--)
{
scanf("%s",s+1);
n=strlen(s+1);cnt=0;last=1;newnode();
for (int i=1;i<=n;i++) ins(s[n-i+1]-'a');
for (int i=1;i<=cnt;i++) f[i][0]=fail[i];f[1][0]=1;
for (int j=1;j<21;j++)
for (int i=1;i<=cnt;i++)
f[i][j]=f[f[i][j-1]][j-1];
na=read();
for (int i=1;i<=na;i++)
{
a[i].l=read(),a[i].r=read();
a[i].r=a[i].r-a[i].l+1;a[i].l=n-a[i].l+1;
}
nb=read();
for (int i=1;i<=nb;i++)
{
b[i].l=read(),b[i].r=read();
b[i].r=b[i].r-b[i].l+1;b[i].l=n-b[i].l+1;
int x=find(id[b[i].l],b[i].r);
node[x].push_back(i);
}
for (int i=1;i<=cnt;i++)
if (!node[i].empty())
{
sort(node[i].begin(),node[i].end(),cmp);
int last=fail[i];
for (int j=0;j<node[i].size();)
{
int x=node[i][j];
if (b[x].r==len[i])
{
for (;j<node[i].size();j++) pos[node[i][j]]=i;
break;
}
len[newnode()]=b[x].r;fail[cnt]=last;last=cnt;
while (j<node[i].size()&&b[node[i][j]].r==len[cnt]) pos[node[i][j]]=cnt,j++;
}
fail[i]=last;
}
for (int i=1;i<=cnt;i++) f[i][0]=fail[i];f[1][0]=1;
for (int j=1;j<21;j++)
for (int i=1;i<=cnt;i++)
f[i][j]=f[f[i][j-1]][j-1];
for (int i=1;i<=cnt+na;i++) F[i]=degree[i]=p[i]=val[i]=0;t=0;
for (int i=cnt+1;i<=cnt+na;i++) val[i]=a[i-cnt].r;
for (int i=2;i<=cnt;i++) addedge(fail[i],i);
for (int i=1;i<=na;i++) addedge(find2(id[a[i].l],a[i].r),cnt+i);
m=read();
for (int i=1;i<=m;i++)
{
int x=read(),y=read();
addedge(cnt+x,pos[y]);
}
cnt+=na;
cout<<topsort()<<endl;
}
return 0;
}