跑一遍dij根据最短路DAG进行拓扑排序,按拓扑序dp即可。wa了三发感觉非常凉。
#include<iostream> #include<cstdio> #include<cmath> #include<cstdlib> #include<cstring> #include<algorithm> #include<queue> using namespace std; #define ll long long #define N 100010 #define M 200010 #define K 51 char getc(){char c=getchar();while ((c<'A'||c>'Z')&&(c<'a'||c>'z')&&(c<'0'||c>'9')) c=getchar();return c;} int gcd(int n,int m){return m==0?n:gcd(m,n%m);} int read() { int x=0,f=1;char c=getchar(); while (c<'0'||c>'9') {if (c=='-') f=-1;c=getchar();} while (c>='0'&&c<='9') x=(x<<1)+(x<<3)+(c^48),c=getchar(); return x*f; } int T,n,m,k,P,p[N],d[N],from[M],f[N][K],Q[N],degree[N],t; bool flag[N]; struct data{int to,nxt,len; }edge[M]; struct data2 { int x,d; bool operator <(const data2&a) const { return d>a.d; } }; priority_queue<data2> q; void inc(int &x,int y){x+=y;if (x>=P) x-=P;} void addedge(int x,int y,int z){t++;edge[t].to=y,edge[t].nxt=p[x],edge[t].len=z;p[x]=t;} void dijkstra() { memset(d,42,sizeof(d));d[1]=0; memset(flag,0,sizeof(flag)); q.push((data2){1,0}); for (;;) { while (!q.empty()&&flag[q.top().x]) q.pop(); if (q.empty()) break; data2 x=q.top();q.pop();flag[x.x]=1; for (int i=p[x.x];i;i=edge[i].nxt) if (x.d+edge[i].len<d[edge[i].to]) { d[edge[i].to]=x.d+edge[i].len; q.push((data2){edge[i].to,d[edge[i].to]}); } } } bool topsort() { memset(degree,0,sizeof(degree)); for (int i=1;i<=m;i++) if (d[from[i]]+edge[i].len==d[edge[i].to]) degree[edge[i].to]++; int head=0,tail=0;for (int i=1;i<=n;i++) if (!degree[i]) Q[++tail]=i; while (head<tail&&tail<n) { int x=Q[++head]; for (int i=p[x];i;i=edge[i].nxt) if (d[x]+edge[i].len==d[edge[i].to]) { degree[edge[i].to]--; if (!degree[edge[i].to]) Q[++tail]=edge[i].to; } } return tail<n; } int main() { T=read(); while (T--) { n=read(),m=read(),k=read(),P=read(); t=0;memset(p,0,sizeof(p)); for (int i=1;i<=m;i++) { int x=read(),y=read(),z=read(); from[i]=x;addedge(x,y,z); } dijkstra(); if (topsort()) cout<<-1<<endl; else { memset(f,0,sizeof(f));f[1][0]=1; for (int i=0;i<=k;i++) for (int j=1;j<=n;j++) { int x=Q[j]; for (int y=p[x];y;y=edge[y].nxt) { int u=d[x]+edge[y].len-d[edge[y].to]+i; if (u<=k) inc(f[edge[y].to][u],f[x][i]); } } int ans=0; for (int i=0;i<=k;i++) inc(ans,f[n][i]); cout<<ans<<endl; } } return 0; }