Calculate a+b and output the sum in standard format – that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input Specification:
Each input file contains one test case. Each case contains a pair of integers a and b where −106≤a,b≤106 . The numbers are separated by a space.
Output Specification:
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input:
-1000000 9
Sample Output:
-999,991
注意下这个点 当c=0的时候while不会进行循环，要不就也可以
改成dowhile，不然就要加if，前面一直以为，是前三位打一个
后面才知道从后卫前三位一个逗号。
if (c == 0) z[num++] = 0;
while (c != 0)
{
z[num++] = c % 10;
c /= 10;
}
#include<iostream>
using namespace std;
int main()
{
int a, b, c = 0;
int z[20] = { 0 }; int num = 0;
int flag = 0;
cin >> a >> b;
c = a + b;
if (c < 0)
{
c = -c;
flag = 1;
}
if (c == 0) z[num++] = 0;
while (c != 0)
{
z[num++] = c % 10;
c /= 10;
}
if (flag)
{
cout << '-';
}
int i = num-1;
while (i!=-1)
{
cout << z[i];
if (i%3==0&&i>0)
{
cout << ',';
}
i--;
}
}