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  • codeforces-1077 (div3)

    复习了一个月的期末考试,搞一套div3热热身

    A.计算出向左向右跳的步直接算

    #include <map>
    #include <set>
    #include <ctime>
    #include <cmath>
    #include <queue>
    #include <stack>
    #include <vector>
    #include <string>
    #include <cstdio>
    #include <cstdlib>
    #include <cstring>
    #include <sstream>
    #include <iostream>
    #include <algorithm>
    #include <functional>
    using namespace std;
    #define For(i, x, y) for(int i=x;i<=y;i++)  
    #define _For(i, x, y) for(int i=x;i>=y;i--)
    #define Mem(f, x) memset(f,x,sizeof(f))  
    #define Sca(x) scanf("%d", &x)
    #define Sca2(x,y) scanf("%d%d",&x,&y)
    #define Sca3(x,y,z) scanf("%d%d%d",&x,&y,&z)
    #define Scl(x) scanf("%lld",&x);  
    #define Pri(x) printf("%d
    ", x)
    #define Prl(x) printf("%lld
    ",x);  
    #define CLR(u) for(int i=0;i<=N;i++)u[i].clear();
    #define LL long long
    #define ULL unsigned long long  
    #define mp make_pair
    #define PII pair<int,int>
    #define PIL pair<int,long long>
    #define PLL pair<long long,long long>
    #define pb push_back
    #define fi first
    #define se second 
    typedef vector<int> VI;
    int read(){int x = 0,f = 1;char c = getchar();while (c<'0' || c>'9'){if (c == '-') f = -1;c = getchar();}
    while (c >= '0'&&c <= '9'){x = x * 10 + c - '0';c = getchar();}return x*f;}
    const double eps = 1e-9;
    const int maxn = 110;
    const int INF = 0x3f3f3f3f;
    const int mod = 1e9 + 7; 
    int N,M,K;
    int main(){
        int T; Sca(T);
        while(T--){
            LL l,r,k;
            scanf("%lld%lld%lld",&l,&r,&k);
            LL a = k / 2,b = k - a;
            Prl(b * l - a * r);
        }
        return 0;
    }
    A

    B.从左到右扫,遇到101就贪心的变成100,因为变成100还可能导致后面的101变成001,变成001就对后面毫无影响

    #include <map>
    #include <set>
    #include <ctime>
    #include <cmath>
    #include <queue>
    #include <stack>
    #include <vector>
    #include <string>
    #include <cstdio>
    #include <cstdlib>
    #include <cstring>
    #include <sstream>
    #include <iostream>
    #include <algorithm>
    #include <functional>
    using namespace std;
    #define For(i, x, y) for(int i=x;i<=y;i++)  
    #define _For(i, x, y) for(int i=x;i>=y;i--)
    #define Mem(f, x) memset(f,x,sizeof(f))  
    #define Sca(x) scanf("%d", &x)
    #define Sca2(x,y) scanf("%d%d",&x,&y)
    #define Sca3(x,y,z) scanf("%d%d%d",&x,&y,&z)
    #define Scl(x) scanf("%lld",&x);  
    #define Pri(x) printf("%d
    ", x)
    #define Prl(x) printf("%lld
    ",x);  
    #define CLR(u) for(int i=0;i<=N;i++)u[i].clear();
    #define LL long long
    #define ULL unsigned long long  
    #define mp make_pair
    #define PII pair<int,int>
    #define PIL pair<int,long long>
    #define PLL pair<long long,long long>
    #define pb push_back
    #define fi first
    #define se second 
    typedef vector<int> VI;
    int read(){int x = 0,f = 1;char c = getchar();while (c<'0' || c>'9'){if (c == '-') f = -1;c = getchar();}
    while (c >= '0'&&c <= '9'){x = x * 10 + c - '0';c = getchar();}return x*f;}
    const double eps = 1e-9;
    const int maxn = 110;
    const int INF = 0x3f3f3f3f;
    const int mod = 1e9 + 7; 
    int N,M,K;
    int a[maxn];
    int main(){
        Sca(N);
        for(int i = 1; i <= N ; i ++){
            Sca(a[i]);
        }
        int k = 0;
        for(int i = 3; i <= N ; i ++){
            if(a[i] && a[i - 2] && !a[i - 1]){
                a[i] = 0;
                k++;
            } 
        }
        Pri(k);
        return 0;
    }
    B

    C.计算和计算出现的次数直接线性算。

    #include <map>
    #include <set>
    #include <ctime>
    #include <cmath>
    #include <queue>
    #include <stack>
    #include <vector>
    #include <string>
    #include <cstdio>
    #include <cstdlib>
    #include <cstring>
    #include <sstream>
    #include <iostream>
    #include <algorithm>
    #include <functional>
    using namespace std;
    #define For(i, x, y) for(int i=x;i<=y;i++)  
    #define _For(i, x, y) for(int i=x;i>=y;i--)
    #define Mem(f, x) memset(f,x,sizeof(f))  
    #define Sca(x) scanf("%d", &x)
    #define Sca2(x,y) scanf("%d%d",&x,&y)
    #define Sca3(x,y,z) scanf("%d%d%d",&x,&y,&z)
    #define Scl(x) scanf("%lld",&x);  
    #define Pri(x) printf("%d
    ", x)
    #define Prl(x) printf("%lld
    ",x);  
    #define CLR(u) for(int i=0;i<=N;i++)u[i].clear();
    #define LL long long
    #define ULL unsigned long long  
    #define mp make_pair
    #define PII pair<int,int>
    #define PIL pair<int,long long>
    #define PLL pair<long long,long long>
    #define pb push_back
    #define fi first
    #define se second 
    typedef vector<int> VI;
    int read(){int x = 0,f = 1;char c = getchar();while (c<'0' || c>'9'){if (c == '-') f = -1;c = getchar();}
    while (c >= '0'&&c <= '9'){x = x * 10 + c - '0';c = getchar();}return x*f;}
    const double eps = 1e-9;
    const int maxn = 2e5 + 10;
    const int maxm = 1e6 + 10;
    const int INF = 0x3f3f3f3f;
    const int mod = 1e9 + 7; 
    int N,M,K;
    int a[maxn];
    int b[maxm];
    vector<int>ans;
    int main(){
        Sca(N);
        LL sum = 0;
        for(int i = 1; i <= N ; i ++){
            Sca(a[i]); b[a[i]]++;
            sum += a[i];
        }
        for(int i = 1; i <= N ; i ++){
            if((sum - a[i]) & 1) continue;
            int flag = 0;
            if((sum - a[i]) / 2 == a[i]) flag = 1;
            if((sum - a[i]) / 2 > 1e6) continue;
            if(b[(sum - a[i]) / 2] > flag) ans.pb(i);
        }
        Pri(ans.size());
        for(int i = 0 ; i < ans.size(); i ++) printf("%d ",ans[i]);
        return 0;
    }
    C

    D.二分一下k个子序列可以在序列中可以重复的最多次数

    #include <map>
    #include <set>
    #include <ctime>
    #include <cmath>
    #include <queue>
    #include <stack>
    #include <vector>
    #include <string>
    #include <cstdio>
    #include <cstdlib>
    #include <cstring>
    #include <sstream>
    #include <iostream>
    #include <algorithm>
    #include <functional>
    using namespace std;
    #define For(i, x, y) for(int i=x;i<=y;i++)  
    #define _For(i, x, y) for(int i=x;i>=y;i--)
    #define Mem(f, x) memset(f,x,sizeof(f))  
    #define Sca(x) scanf("%d", &x)
    #define Sca2(x,y) scanf("%d%d",&x,&y)
    #define Sca3(x,y,z) scanf("%d%d%d",&x,&y,&z)
    #define Scl(x) scanf("%lld",&x);  
    #define Pri(x) printf("%d
    ", x)
    #define Prl(x) printf("%lld
    ",x);  
    #define CLR(u) for(int i=0;i<=N;i++)u[i].clear();
    #define LL long long
    #define ULL unsigned long long  
    #define mp make_pair
    #define PII pair<int,int>
    #define PIL pair<int,long long>
    #define PLL pair<long long,long long>
    #define pb push_back
    #define fi first
    #define se second 
    typedef vector<int> VI;
    int read(){int x = 0,f = 1;char c = getchar();while (c<'0' || c>'9'){if (c == '-') f = -1;c = getchar();}
    while (c >= '0'&&c <= '9'){x = x * 10 + c - '0';c = getchar();}return x*f;}
    const double eps = 1e-9;
    const int maxn = 2e5 + 10;
    const int INF = 0x3f3f3f3f;
    const int mod = 1e9 + 7; 
    int N,M,K;
    int a[maxn],b[maxn];
    int MAX,MIN;
    bool check(int x){
        LL ans = 0;
        for(int i = MIN; i <= MAX; i ++){
            ans += b[i] / x;    
        }
        return ans >= K;
    }
    int solve(){
        int l = 1,r = N;
        int ans = 0;
        while(l <= r){
            int m = l + r >> 1;
            if(check(m)){
                ans = m;
                l = m + 1;
            }else{
                r = m - 1;
            }
        }
        return ans;
    }
    vector<int>A;
    int main(){
        Sca2(N,K);
        MAX = 0, MIN = INF;
        for(int i = 1; i <= N ; i ++){
            Sca(a[i]); b[a[i]] ++;
            MAX = max(MAX,a[i]);
            MIN = min(MIN,a[i]);
        }
        int x = solve();
        for(int i = MIN; i <= MAX ; i ++){
            while(b[i] >= x){
                b[i] -= x;
                A.pb(i);
            }
        }
        for(int i = 0 ; i < K ; i++) printf("%d ",A[i]);
        return 0;
    }
    D

    E.统计出所有数出现的次数从小到大排序。

    dp[i]表示最小的数为i的时候答案最大是多少,更新答案就相当于往前塞更小的数。

    #include <map>
    #include <set>
    #include <ctime>
    #include <cmath>
    #include <queue>
    #include <stack>
    #include <vector>
    #include <string>
    #include <cstdio>
    #include <cstdlib>
    #include <cstring>
    #include <sstream>
    #include <iostream>
    #include <algorithm>
    #include <functional>
    using namespace std;
    #define For(i, x, y) for(int i=x;i<=y;i++)  
    #define _For(i, x, y) for(int i=x;i>=y;i--)
    #define Mem(f, x) memset(f,x,sizeof(f))  
    #define Sca(x) scanf("%d", &x)
    #define Sca2(x,y) scanf("%d%d",&x,&y)
    #define Sca3(x,y,z) scanf("%d%d%d",&x,&y,&z)
    #define Scl(x) scanf("%lld",&x);  
    #define Pri(x) printf("%d
    ", x)
    #define Prl(x) printf("%lld
    ",x);  
    #define CLR(u) for(int i=0;i<=N;i++)u[i].clear();
    #define LL long long
    #define ULL unsigned long long  
    #define mp make_pair
    #define PII pair<int,int>
    #define PIL pair<int,long long>
    #define PLL pair<long long,long long>
    #define pb push_back
    #define fi first
    #define se second 
    typedef vector<int> VI;
    int read(){int x = 0,f = 1;char c = getchar();while (c<'0' || c>'9'){if (c == '-') f = -1;c = getchar();}
    while (c >= '0'&&c <= '9'){x = x * 10 + c - '0';c = getchar();}return x*f;}
    const double eps = 1e-9;
    const int maxn = 2e5 + 10;
    const int INF = 0x3f3f3f3f;
    const int mod = 1e9 + 7; 
    int N,M,K;
    map<int,int>P;
    int b[maxn],a[maxn],dp[maxn * 2];
    int main(){
        Sca(N); 
        int cnt = 0;
        for(int i = 1; i <= N ; i ++){
            Sca(a[i]);
            if(!P[a[i]]) P[a[i]] = ++cnt;
            b[P[a[i]]]++;
        }
        sort(b + 1,b + 1 + cnt);
        int ans = 0;
        for(int i = cnt ; i >= 1; i --){
            for(int j = 1; j <= b[i]; j ++){
                dp[j] = max(dp[j],dp[j * 2] + j);
                ans = max(ans,dp[j]);
            }
        }
        Pri(ans);
        return 0;
    }
    E
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  • 原文地址:https://www.cnblogs.com/Hugh-Locke/p/11137173.html
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