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  • Codeforces Round #424 (Div. 2) A-C

    A. Unimodal Array

    水题

    #include <iostream>
    #include <cstring>
    #include <cstdio>
    #include <algorithm>
    #include <queue>
    #include <vector>
    #include <iomanip>
    #include <math.h>
    #include <map>
    using namespace std;
    #define FIN     freopen("input.txt","r",stdin);
    #define FOUT    freopen("output.txt","w",stdout);
    #define INFLL   0x3f3f3f3f3f3f3f
    #define lson    l,m,rt<<1
    #define rson    m+1,r,rt<<1|1
    typedef long long LL;
    typedef pair<double, double> PII;
    
    const int maxn = 100 + 5;
    
    int a[maxn];
    int b[maxn];
    
    int main() {
        //FIN
        int n;
        cin >> n;
        for(int i = 1; i <= n; i++) cin >> a[i];
        for(int i = 1; i <= n -1; i++) {
            if(a[i] - a[i + 1] > 0) b[i] = 1;
            else if(a[i] - a[i + 1] == 0) b[i] = 0;
            else if(a[i] - a[i + 1] < 0) b[i] = -1;
        }
        for(int i = 1; i <= n - 2; i++) {
            //cout << b[i]<<"  ";
            if(b[i + 1] < b[i]) {
                cout <<"NO"<<endl;
                return 0;
            }
        }
        cout <<"YES"<<endl;
        return 0;
    }
    

      

    B. Keyboard Layouts

    比第一题还水...

    #include <iostream>
    #include <cstring>
    #include <cstdio>
    #include <algorithm>
    #include <queue>
    #include <vector>
    #include <iomanip>
    #include <math.h>
    #include <map>
    using namespace std;
    #define FIN     freopen("input.txt","r",stdin);
    #define FOUT    freopen("output.txt","w",stdout);
    #define INFLL   0x3f3f3f3f3f3f3f
    #define lson    l,m,rt<<1
    #define rson    m+1,r,rt<<1|1
    typedef long long LL;
    typedef pair<double, double> PII;
    
    char s1[30];
    char s2[30];
    char s3[1005];
    
    int main() {
        //FIN
        cin >> s1;
        cin >> s2;
        cin >> s3;
        int len = strlen(s3);
        for(int i = 0; i < len; i++) {
            int flag = 0;
            if(s3[i] >= '0' && s3[i] <= '9') {
                cout << s3[i];
                continue;
            }
            if(s3[i] >= 'A' && s3[i] <= 'Z') {
                flag = 1;
                s3[i] += 32;
            }
            for(int j = 0; j < 26; j++) {
                if(s1[j] == s3[i]) {
                    if(flag) printf("%c", s2[j] - 32);
                    else cout << s2[j] ;
                    break;
                }
            }
    
        }
    
        return 0;
    }
    

      

    C. Jury Marks

    这题看了题解才会做 学会了一个新操作 unique

    #include <iostream>
    #include <cstring>
    #include <cstdio>
    #include <algorithm>
    #include <queue>
    #include <vector>
    #include <iomanip>
    #include <math.h>
    #include <map>
    using namespace std;
    #define FIN     freopen("input.txt","r",stdin);
    #define FOUT    freopen("output.txt","w",stdout);
    #define INFLL   0x3f3f3f3f3f3f3f
    #define lson    l,m,rt<<1
    #define rson    m+1,r,rt<<1|1
    typedef long long LL;
    typedef pair<double, double> PII;
    
    const int maxn = 2000 + 5;
    
    int a[maxn];
    int b[maxn];
    int sum[maxn];
    
    vector<int> vec;
    map<int, int> mp;
    
    int main() {
        //FIN
        int n, k;
        scanf("%d%d", &k, &n);
        int x;
        for(int i = 1; i <= k; i++) {
            scanf("%d", &a[i]);
            sum[i] += sum[i - 1] + a[i];
        }
    
        sort(sum + 1, sum + 1 + k);
        int len = unique(sum + 1, sum + 1 + k) - (sum + 1);
    
        for(int i = 1; i <= n; i++) {
            scanf("%d", &b[i]);
            for(int j = 1; j <= len; j++) {
                int tmp = b[i] - sum[j];
                vec.push_back(tmp);
            }
        }
    
        sort(vec.begin(), vec.end());
    
        for(int i = 0; i < vec.size(); i++) {
            mp[vec[i]]++;
        }
    
        int ans = 0;
    
        for(int i = 0; i < vec.size(); i++) {
            if(mp[vec[i]] >= n) {
                ans++;
                mp[vec[i]] = 0;
            }
        }
        printf("%d
    ", ans);
    
        return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/Hyouka/p/7327888.html
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