Codeforces Gym

I. Rock Piles

time limit per test

1.0 s

memory limit per test

256 MB

input

standard input

output

standard output

Hasan and Abdullah are lost in the desert, they are waiting for the rescue squad to help them. While they are waiting, they decided to invent a new game called Rock Piles.

In this game, there are two rock piles. The first pile contains N rocks, and the second one contains M rocks. Hasan and Abdullah take turns to play the game, Hasan starts first. In each turn, a player can choose to take one rock from a single pile, or take one rock from both piles. The player who cannot make any move, loses the game. Determine who will win if both of them play optimally.

Input

The first line of the input contains an integer T (1  ≤  T  ≤  104), where T is the number of the test cases.

Each test case has one line that contains two integers N and M (0  ≤  N, M  ≤  109), the number of rocks in the first and second pile respectively.

Output

For each test case, print a single line with the winner's name. If Hasan wins print "hasan", otherwise print "abdullah" (without quotes).

Example

input

2
2 3
4 0

output

hasan
abdullah

 威佐夫博弈的变形  变形了那跟原来的关系应该就不大了 在纸上写了几个状态没发现规律 只好SG函数打表

打出表后规律一下就清楚了

#include <iostream>
#include <cstring>
#include <cstdio>
#include <algorithm>
#include <queue>
#include <vector>
#include <iomanip>
#include <math.h>
#include <map>
using namespace std;
#define FIN     freopen("input.txt","r",stdin);
#define FOUT    freopen("output.txt","w",stdout);
#define INF     0x3f3f3f3f
#define INFLL   0x3f3f3f3f3f3f3f
#define lson    l,m,rt<<1
#define rson    m+1,r,rt<<1|1
typedef long long LL;
typedef pair<int, int> PII;
using namespace std;

const int maxn = 10000 + 5;
/*
void GetSG(int n = 100, int m = 100) {
    int i, j;
    memset(SG, 0, sizeof(SG));
    for(i = 0; i <= n; i++) {
        for(int j = 0; j <= m; j++) {
            memset(Hash, 0, sizeof(Hash));
            if(i >= 1) Hash[SG[i - 1][j]] = 1;
            if(j >= 1) Hash[SG[i][j - 1]] = 1;
            if(i >= 1 && j >= 1) Hash[SG[i - 1][j - 1]] = 1;
            for(int k = 0; k <= n; k++) {
                if(Hash[k] == 0) {
                     SG[i][j] = k;
                     break;
                }
            }
        }
    }
}
*/
int main() {
    //FIN
    int n, m;
    int T;
    scanf("%d", &T);
    while(T--) {
        scanf("%d%d", &n, &m);
        if(n % 2 == 0 && m % 2 == 0) puts("abdullah");
        else puts("hasan");
    }

    return 0;
}